Observing Spectral Lines: The Highest Order & Color Sequence

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SUMMARY

The discussion centers on determining the highest observable order of spectral lines for Hydrogen using a spectrometer with a diffraction grating of 500 lines/mm. The highest order of spectrum (m) for the 656.3nm line is conclusively 3, while for the 410.1nm line, it is 4; however, since both lines must be fully observed, the effective highest order is 3. The sequence of colors observed as the spectrometer is rotated through 90 degrees is identified as Violet, Red, Violet, Violet, Red, Violet, Red. The sine function's monotonic increase confirms that the observed angles do not alter the order.

PREREQUISITES
  • Understanding of diffraction grating principles
  • Familiarity with the equation mλ = d sin θ
  • Knowledge of spectral lines and their wavelengths
  • Basic concepts of color perception in light spectra
NEXT STEPS
  • Study the principles of diffraction grating and its applications in spectroscopy
  • Learn about the calculation of spectral lines using the mλ = d sin θ formula
  • Explore the properties of light and color perception in physics
  • Investigate the behavior of sine functions in relation to wave phenomena
USEFUL FOR

Students and educators in physics, particularly those focusing on optics and spectroscopy, as well as researchers analyzing spectral data from various light sources.

elevenb
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Homework Statement



In a question I was asked, assuming a spectrometer reading of Hydrogen produced two strong spectral lines at 656.3nm and 410.1nm. And also assuming the diffraction grating had 500 lines/mm

What is the highest order of spectrum which can be fully observed , i.e value of m.

and assuming the physicist begins with the spectrometer telescope eyepiece at a deviation angle of zero and rotates it through 90 degrees, determine the sequence of line colours that she sees?

Homework Equations



mλ=dsinθ

The Attempt at a Solution

I worked out that the highest value of m for the 656.3nm line is 3 and for the 410.1nm line it's four but because it says fully observed I said three because the two lines can be observed fully at this order of spectrum.

For the second part I wrote out multiples of the wavelengths, I got

410.1, 820.2, 1230.3, 1640.4

656.3, 1312.6, 1968.9

So if I call the 410.1nm one violet, and the 656.3nm one red. Are the colours she sees

Violet, red, violet, violet, red, violet, red?
 
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mc94 said:

Homework Statement



In a question I was asked, assuming a spectrometer reading of Hydrogen produced two strong spectral lines at 656.3nm and 410.1nm. And also assuming the diffraction grating had 500 lines/mm

What is the highest order of spectrum which can be fully observed , i.e value of m.

and assuming the physicist begins with the spectrometer telescope eyepiece at a deviation angle of zero and rotates it through 90 degrees, determine the sequence of line colours that she sees?

Homework Equations



mλ=dsinθ

The Attempt at a Solution

I worked out that the highest value of m for the 656.3nm line is 3 and for the 410.1nm line it's four but because it says fully observed I said three because the two lines can be observed fully at this order of spectrum.

For the second part I wrote out multiples of the wavelengths, I got

410.1, 820.2, 1230.3, 1640.4

656.3, 1312.6, 1968.9

So if I call the 410.1nm one violet, and the 656.3nm one red. Are the colours she sees

Violet, red, violet, violet, red, violet, red?

The result is correct, but the physicist observes angles. It does not change the order as the sine function is monotonously increases with your multiples of wavelengths.

ehild
 

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