# Odd Arrangement - Isolate the term "Ru" in V/(Vin*R)=(1/(R+Ru*k))-(1/(R+Ru))

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• Outdoors
In summary, the conversation revolves around finding a solution for the equation V/(Vin*R)=(1/(R+Ru*k))-(1/(R+Ru)) where all values except for Ru are known. The participants discuss different approaches, such as using the Quadratic Formula, and eventually come to the conclusion that the best method is to put the equation in quadratic form. One of the participants notes that they were rusty and it took some time, but they were able to find a clean solution.
Outdoors
I thought my algebra skills were good, but this problem has me frustrated. I would like to rearrange the equation to solve for Ru, but I can't seem to get Ru isolated. All values are known except for Ru.

Re: Odd Arrangement - Isolate Ru

Well, what did you do first? You'll have to get Ru out of the denominators.

Two different denominators? I'm guessing you'll need your Quadratic Formula. Can you figure out which solution will be acceptable?

Re: Odd Arrangement - Isolate Ru

Welcome to MHB!

Hint: I would try grouping the RHS into a single fraction (find a common denominator), and then 'crank the handle'. i.e. multiply and group terms, you should end up with a quadratic in $R_{\rm u}$.

Edit: whoops, tkhunny beat me to it!

Re: Odd Arrangement - Isolate Ru

tkhunny said:
Well, what did you do first? You'll have to get Ru out of the denominators.

Two different denominators? I'm guessing you'll need your Quadratic Formula. Can you figure out which solution will be acceptable?

While you were able to see it more quickly, I've finally come to the same conclusion. I was able to put the equation in a quadratic form, equal to zero. Thank you for your help.

- - - Updated - - -

Joppy said:
Welcome to MHB!

Hint: I would try grouping the RHS into a single fraction (find a common denominator), and then 'crank the handle'. i.e. multiply and group terms, you should end up with a quadratic in $R_{\rm u}$.

Edit: whoops, tkhunny beat me to it!
While you were able to see it more quickly, I've finally come to the same conclusion. I was able to put the equation in a quadratic form, equal to zero. Thank you for your help.

Re: Odd Arrangement - Isolate Ru

Outdoors said:
While you were able to see it more quickly, I've finally come to the same conclusion. I was able to put the equation in a quadratic form, equal to zero. Thank you for your help.

Good work! Was it messier than you expected?

Re: Odd Arrangement - Isolate Ru

tkhunny said:
Good work! Was it messier than you expected?
All the previous approaches were messy. The approach that led to the quadratic form was clean. It all took way too long though. Rusty I guess.

Re: Odd Arrangement - Isolate Ru

Outdoors said:
All the previous approaches were messy. The approach that led to the quadratic form was clean. It all took way too long though. Rusty I guess.
Perfect. Hang in there. You're getting back up to speed already!

## 1. What does "Ru" represent in the equation?

"Ru" represents the unknown resistance value that needs to be isolated.

## 2. How can I isolate the term "Ru" in the equation?

To isolate "Ru", you can use algebraic manipulation to rearrange the equation and solve for "Ru".

## 3. Can the equation be simplified further?

Yes, the equation can be simplified by combining like terms and using the distributive property.

## 4. Can the equation be solved for multiple values of "Ru"?

Yes, the equation can be solved for multiple values of "Ru" as long as the other variables are known.

## 5. How can I use this equation in a scientific experiment?

This equation can be used to calculate the unknown resistance value in a circuit, which can be useful in various scientific experiments involving electricity and electronics.

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