ODE question: Understanding a step in the solution

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The discussion focuses on understanding a step in the solution of the ordinary differential equation (ODE) y'' + y = g(t) using variation of parameters. The user seeks clarification on how the first matrix transforms into the subsequent one in the provided solution. There is confusion regarding the representation of the terms in the matrix, specifically whether they should include complex components like cos(t) + isin(t) instead of just cos(t). The solution involves Gaussian elimination to simplify the matrix. Overall, the thread emphasizes the importance of clarity in notation and matrix transformations in solving ODEs.
Bonnie
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Homework Statement


Hi there, I don't nee help with solving a question, so much as understanding a step in the provided worked solution. It's using variation of parameters to solve the ode y''+ y = g(t). I've attached the steps in the picture file, and the bit after the word 'Now' what are they doing to the first matrix in order to get the one following the arrow? It might be really obvious but I don't quite get what they've done.

Aso, since y1 = eit and y2 = e-it, shouldn't the terms in the very first matrix listed (before the ones I referred to earlier) be cos(t)+isin(t) (eg. for the first entry) etc, instead of just cos(t)?
Many thanks

Homework Equations

The Attempt at a Solution

 

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I could not follow the second step=the notation seems unclear, but the first matrix has a very obvious inverse if you are familiar with the equations that do a rotation of axes. Using this it is very easy to get the identity matrix on the left side that is multiplied by the column vector ## (u_1', u_2') ##.
 
Bonnie said:
what are they doing to the first matrix in order to get the one following the arrow?
Gaussian elimination

Bonnie said:
y1 = eit and y2 = e-it
The author of the solution used different expressions for ##y_1## and ##y_2##. Given the matrices in your attachment, you should be able to guess what they are.
 
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