On conditional probability of an exponential random variable

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SUMMARY

The discussion centers on calculating the conditional probability of the fractional part of an exponential random variable, specifically P(Z < z | Y = n). The random variable X is defined with the probability density function f(x) = λ exp(-λ x), where Y represents the integral part and Z the fractional part of X. The derived formula for the conditional probability is P(Z < z | Y = n) = (1 - e^(-λz)) / (1 - e^(-λ)), applicable for 0 ≤ z < 1 and n = 0, 1, … .

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Postante
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You are given a random exponential variable X: f(x) = λ exp(-λ x).
Suppose that X = Y + Z, where Y is the integral part of X and Z is the fractional part of X:
Y = IP(X), Z = FP(X).
Which is the following conditional probability:
P(Z < z | Y = n) for 0 ≤ z < 1 and n = 0, 1, … ?
 
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Postante said:
You are given a random exponential variable X: f(x) = λ exp(-λ x).
Suppose that X = Y + Z, where Y is the integral part of X and Z is the fractional part of X:
Y = IP(X), Z = FP(X).
Which is the following conditional probability:
P(Z < z | Y = n) for 0 ≤ z < 1 and n = 0, 1, … ?
P(Z < z | Y = n) = P(X < n+z | Y = n) = P(X < n+z | n <= X < n+1)
= (F(n+z)-F(n))/(F(n+1) - F(n))
= (e-λn - e-λ(n+z))/(e-λn - e-λ(n+1))
= (1-e-λz)/(1-e)
 

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