On length contraction (Special Relativity)

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Homework Help Overview

The problem involves understanding the concept of length contraction in the context of special relativity, specifically how a sphere in motion deforms into an oblate rotational ellipsoid. The original poster expresses confusion regarding the deformation of the sphere and the factors involved in calculating the volume of the resulting shape.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand why the sphere deforms into an oblate spheroid rather than a prolate spheroid, questioning the assumptions about contraction in different dimensions. Some participants discuss which dimensions (equatorial or polar) are affected by length contraction and how this impacts volume calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding which dimensions are contracted, but there is no explicit consensus on the correct approach or final outcome.

Contextual Notes

Participants are navigating the complexities of volume calculations and the implications of length contraction, with some expressing uncertainty about their understanding of the concepts involved.

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Homework Statement


Show that the length contraction deforms a sphere in motion to an oblate rotational ellipsoid whose volume decreases by a factor of γ (gamma)


Homework Equations


x=x'/γ v=4∏r^3/3 (volume for sphere) v=4∏(a^2)b/3 (volume for prolate and oblate spheroid)


The Attempt at a Solution


The question is taken from Special relativity for beginners by Jurgen Freund. Firstly, I am confused as to why the question claims that the sphere would deform into an oblate spheroid rather than a prolate spheroid since length contraction does not contract transversely. Anyway by length contraction, the radius (r) of the sphere would contract by a factor of γ, Therefore:
r=a/γ where a is the equatorial radius and b is the polar radius. By subbing r=a/γ into the formula of sphere, through some algebraic manipulation, I get a spheroid whose radius decreased by a factor of γ^3 instead. How should I go about doing it and where are my errors ?

Please help.

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So what happens to the sphere with the length contraction? The direction parallel to motion is contracted, and the two perpendicular to it are not, right? So which of a and b are transformed?
 
The equatorial radius (a) of the prolate spheroid would be contracted by a factor of γ. (i.e a=r/γ). Therefore the volume of the sphere is V=4∏(r^3)/3 and the volume of the prolate spheroid would be V'=4∏(r^2)b/3(γ^2). Finally, taking the volume of the sphere and divide it by the volume of the prolate spheroid gives (V/V')=r(γ^2)/b ??

Sorry if I am slow at catching ideas. Please bear with me.

Thank you very much
 
physikamateur said:
The equatorial radius (a) of the prolate spheroid would be contracted by a factor of γ. (i.e a=r/γ). Therefore the volume of the sphere is V=4∏(r^3)/3 and the volume of the prolate spheroid would be V'=4∏(r^2)b/3(γ^2). Finally, taking the volume of the sphere and divide it by the volume of the prolate spheroid gives (V/V')=r(γ^2)/b ??

Sorry if I am slow at catching ideas. Please bear with me.

Thank you very much

Watch out. It is b which is contracted whereas "a" remains equal to the initial radius.
 
physikamateur said:
The equatorial radius (a) of the prolate spheroid would be contracted by a factor of γ. (i.e a=r/γ).

Why?
 

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