On the definition of Von Neumann entropy

Click For Summary

Discussion Overview

The discussion revolves around the definition and calculation of Von Neumann entropy, particularly focusing on the mathematical interpretation of the logarithm of a density matrix. Participants explore various methods for calculating the entropy and the implications of matrix properties on these calculations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses confusion regarding the definition of the logarithm of a matrix, questioning whether it is defined through a series expansion or an element-wise approach.
  • Another participant provides a series expansion for the logarithm of a matrix, suggesting a method to define log A using a convergent series.
  • A third participant proposes that diagonalizing the density matrix \(\rho\) simplifies the calculation of Von Neumann entropy, leading to a specific expression involving the eigenvalues of \(\rho\).
  • A later reply confirms the proposed method for calculating \(S(\rho)\) using the diagonalized form of the matrix.

Areas of Agreement / Disagreement

While there is a confirmation of the method proposed for calculating \(S(\rho)\), the initial confusion regarding the logarithm of a matrix indicates that multiple interpretations or approaches may exist, and the discussion does not reach a consensus on the definition of the logarithm itself.

Contextual Notes

The discussion highlights potential limitations in understanding the logarithm of matrices, particularly in non-diagonal cases, and the dependence on the convergence of series expansions for defining matrix logarithms.

univector
Messages
15
Reaction score
0
I am confused by the definition of the Von Neumann entropy. In Nielson and Chung's book page 510, the Von Neumann entropy is defined as
S (\rho) = - tr(\rho \log \rho)
where \rho is the density matrix. What is the definition of the logrithm of a matrix? Is it some series expansion of a matrix, or an element-by-element logrithm?

Thanks.
 
Physics news on Phys.org
Note that

\frac{d}{dx}\log(1+x)=\frac{1}{1+x}=1-x+x^2-x^3+\cdots

Integrate.

\log(1+x)=x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+\cdots

Now set y=1+x.

\log y=(y-1)-\frac{(y-1)^2}{2}+\cdots=\sum_{k=1}^\infty(-1)^{k+1}\frac{(y-1)^k}{k}

This suggests that if A is a matrix, we can define log A by

\log A=\sum_{k=1}^\infty(-1)^{k+1}\frac{(A-I)^k}{k}

for all matrices A such that the series converges. More information here.
 
Last edited:
Hi Fredrik,

Thanks for the explanation. If the matrix \rho is not diagonal, it is not trivial to calculate the matrix polynomial series. Instead, if we do a similary transform to diagonize \rho first, things may become easier. Let the diagonal matrix be D. Then by using the series expansion forward (for a matrix) and backward (for a number), we can come up with
S(\rho) = tr (D M),
where
M = \left( \begin{array}{cccc} \log \lambda_1 &amp; 0 &amp; 0 &amp; ... \\<br /> 0 &amp; \log \lambda_2 &amp; 0 &amp; ... \\<br /> ... &amp; ... &amp; ... &amp; ... \\<br /> 0 &amp; ... &amp; 0 &amp; \log \lambda_n<br /> \end{array} \right)
where \lambda_i is the ith engenvalue of matrix \rho (or D), and n is the number of rows (also columns) of \rho .

Is this the way people calculate S(\rho)?
 
Yes.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
7K
  • · Replies 1 ·
Replies
1
Views
2K