- #1

HansLee

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[tex]\partial[/tex]u / [tex]\partial[/tex]t = k ([tex]\partial[/tex]

^{2}u / [tex]\partial[/tex]x

^{2})-2u (0< x <1)

u(x,0)=e

^{-x}

u(0,t)=e

^{-2t}

u(1,t)=0

I need to solve it with separation variable

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- Thread starter HansLee
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- #1

HansLee

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- 0

[tex]\partial[/tex]u / [tex]\partial[/tex]t = k ([tex]\partial[/tex]

u(x,0)=e

u(0,t)=e

u(1,t)=0

I need to solve it with separation variable

- #2

Office_Shredder

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Ok... what have you done so far? Do you know how to start a problem like this?

- #3

HansLee

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No, I have no idea how to start it, bcos it's non-homogeneous eq, can u help me?

- #4

Office_Shredder

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If you're actually trying to solve the heat equation, then start with u(x,t) = X(x)T(t) for some X and T functions and then try to separate the x's and the t's

- #5

HallsofIvy

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[tex]X\frac{du}{dt}= \kappa T\frac{d^2X}{dx^2}- 2XT[/tex]

divided through by XT and see what happens.

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