One dimensional Schroedinger equation solution

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SUMMARY

The discussion focuses on solving the one-dimensional Schrödinger equation for a particle before a potential barrier, where the wave function is expressed as ψ(x) = B*sin(kx-∅). The user correctly identifies that for regions where U(x) = 0, the energy equation simplifies to Eψ(x) = -(ħ²/2m)(d²ψ(x)/dx²). The user derives the relationship E = ħ²k²/2m and attempts to relate wave number k to the de Broglie wavelength, ultimately seeking clarification on the correct expression for k.

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Homework Statement


before a potential barrier show;
ψ(x) = B*sin(kx-∅)
B, k and ∅ are all possitive

Is a solution of the one dimensional Schroedinger equation

Homework Equations


ψ(x) = B*sin(kx-∅)
Eψ(x) = -(ħ2/2m)(d2ψ(x)/dx2)+U(x)ψ(x)

The Attempt at a Solution


If it is before the barrier U(x) = 0 so;
Eψ(x) = -(ħ2/2m)(d2ψ(x)/dx2)

ψ(x) = B*sin(kx-∅)
dψ(x)/dx= Bk*cos(kx-∅)
(d2ψ(x)/dx2) = -Bk2*sin(kx-∅)

By substitution;
E = ħ22k2/2m
λ = h/p (de broglie wavelength)
p = mv
h = λmv
so k = 2π√(2Em) / λmv
??
apparently I should get;
k=2π/λ
What I have is a multiple of 2π/λ
What have I done wrong / what else should I do
Thanks in advance for and help you offer
 
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E = 0.5 * m * v^2 I got it :)
 

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