Optics aperture modeling rect functions

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SUMMARY

The discussion focuses on modeling a shape T aperture using 2D rectangular (rect) functions, specifically addressing the combination of horizontal and vertical lines defined by dimensions 'a' and 'b'. The user expresses confusion regarding the addition and multiplication of rect functions, particularly in defining the vertical and horizontal components of the aperture. The user proposes expressions for both components but struggles with the concept of Cartesian separability and the proper mathematical operations to combine these functions. The need for clarity on how to express these rect functions in a unified manner is emphasized.

PREREQUISITES
  • Understanding of 2D rectangular functions (rect functions)
  • Familiarity with Cartesian coordinates and separability
  • Basic knowledge of vector notation and operations
  • Experience with mathematical modeling in optics
NEXT STEPS
  • Research the mathematical properties of rectangular functions and their operations
  • Study Cartesian separability in the context of optical modeling
  • Explore vector calculus, specifically in relation to rect functions
  • Investigate the application of rect functions in optics and signal processing
USEFUL FOR

This discussion is beneficial for optical engineers, mathematicians, and students involved in modeling optical systems, particularly those working with rect functions and Cartesian coordinates.

binbagsss
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I am trying to model a shape T aperture through 2D rect functions. Both the horizontal and vertical 'lines' have length b and width a, and do not overlap. The origin should be taken to be the centre of the vertical line.

The question has hinted at the function describing the aperture to be cartesian seperable.

My issues, I think, seem to stem from not knowing how the rect functions can be combined through operations together...

Here are my thoughts on the vertical 'line' :

The RHS of it (to the right of the origin) I believe is: \frac{a}{2} rect \frac{y}{b} [1]
Similarly the LHS i think is : -\frac{a}{2}rect\frac{y}{b}. [2]

My problem is then to express these two together. I am not sure how you define [1] + [2].
Would this be zero?

Perhaps you should multiply them, in which case I get -\frac{a^{2}}{4} rect^{2} \frac{y}{b}; so to me it then makes more sense to look at \frac{a}{2} rect^{2} \frac{y}{b}

Again I'm not sure how you would define a rect^{2} function.

Here are my thoughts on the horizontal 'line' :

First of all, it can not be a single rect function as either the top or bottom line would then be missing.

I think \frac{b}{2} e_{2} - \frac{a}{2}rect\frac{x}{b} for the bottom half, and (\frac{b}{2} + \frac{a}{2} )e_{2} + \frac{a}{2}rect \frac{x}{b} for the top half.

BUT as said above, the question hints towards the function being Cartesian separable, but in describing the horizontal 'line' I have introduced e_{2} - the unit vector in the y direction. This also doesn't look right in general, as isn't rect a scalar ?


Many thanks to anyone who can help shed some light .
!
 
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