Optimal Degree for Approximating Cosine with Taylor Series

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Homework Help Overview

The discussion revolves around determining the appropriate degree of a Taylor polynomial centered at a = 0 (Maclaurin series) required to approximate cos(0.25) to five decimal places of accuracy. Participants are exploring the Taylor series and the associated remainder term for this approximation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand how to apply the remainder term of the Taylor series and are questioning how to determine the value of M when the (n+1)th derivative is unknown. There is also discussion about calculating terms from the series directly to achieve the desired accuracy.

Discussion Status

The conversation is ongoing, with participants sharing their understanding of the remainder method and the derivatives of cosine. Some guidance has been offered regarding the nature of the derivatives, but there is no explicit consensus on how to proceed with the calculations or the choice of t for the derivatives.

Contextual Notes

Participants note that the solution must adhere to the remainder method, and there is uncertainty regarding the specific values to use in calculations, particularly for t in the context of the derivatives.

hadroneater
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Homework Statement


What degree Taylor Polynomial around a = 0(MacLaurin) is needed to approximate cos(0.25) to 5 decimals of accuracy?


Homework Equations


taylor series...to complicated to type out here

remainder of nth degree taylor polynomial = |R(x)| <= M/(n+1)! * |x - a|^(n+1)
where a = 0 in this case
and
M >= |f^(n+1)(t)|



The Attempt at a Solution


I don't really get this question at all. I know that |R(0.25)| = 0.00001 <= M/(n+1)! * |x - a|^(n+1)
But how do I get M when |f^(n+1)(t)| is unknown? I don't even know what |f^(n+1)(t)| means!
 
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hadroneater said:

The Attempt at a Solution


I don't really get this question at all. I know that |R(0.25)| = 0.00001 <= M/(n+1)! * |x - a|^(n+1)
But how do I get M when |f^(n+1)(t)| is unknown? I don't even know what |f^(n+1)(t)| means!

f(n+1)(t) is the n+1:th derivative of f(t). So is your plan to find the lowest upper bound for Mn? It might be easier (and more likely to be correct too) if you just calculated enough terms from the series until you have the desired accuracy.
 
But we aren't marked on that...it has to be through the remainder method.

Anyways, I know what f^(n+1)(t). I just don't know what to plug in for t. And after that, doesn't it just become a plug-and-check game for n until I get less than 0.00001?
 
All derivatives of cosine are [itex]\pm cosine[/itex] or [itex]\pm sine[/itex]. What is the largest possible value of a sine or cosine?
 

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