Optimization isosceles triangle problem

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Homework Help Overview

The problem involves finding the angle theta that maximizes the area of an isosceles triangle with legs of length l. The triangle's configuration is described, with the top angle being theta and the base being horizontal.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use trigonometric identities to express the area of the triangle and considers taking the derivative to find the maximum area. Some participants question the number of variables involved in the derivative process, while others suggest that l is a constant constraint.

Discussion Status

Participants are exploring different approaches to derive the angle theta. Some guidance has been offered regarding the treatment of l as a constant, and there is an ongoing discussion about the correctness of the derived angle of 90 degrees.

Contextual Notes

There is a mention of potential confusion regarding the number of variables in the problem setup, as well as the implications of treating l as a constant constraint in the context of optimization.

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Homework Statement



Find the angle theta that maximizes the area of an isosceles triangle whose legs have length l. The angle is the top angle if the left and right sides are l coming to a point with the bottom leg horizontal.

Homework Equations





The Attempt at a Solution



I broke the triangle up into two halves to use right angle trig and eventually got the area to equal A=l^2 * sin(theta/2)*cos(theta/2). When I took the derivative though I realized that I would have too many variables. I think there's a way to solve for l in terms of theta or theta in terms of l but I'm not sure how to do it can anyone point me in the right direction.
 
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Why do you think you have to many variables? l is a constant. It's a constraint.
 
in that case I used 1/2*l^2*sin(theta) took the derivative got 1/2*l^2*cos(theta)=0 and got theta to be 90 degrees is this correct?
 
Yes, I think so.
 

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