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## Homework Statement

Find the angle theta that maximizes the area of an isosceles triangle whose legs have length

*l*. The angle is the top angle if the left and right sides are

*l*coming to a point with the bottom leg horizontal.

## Homework Equations

## The Attempt at a Solution

I broke the triangle up into two halves to use right angle trig and eventually got the area to equal A=

*l*^2 * sin(theta/2)*cos(theta/2). When I took the derivative though I realized that I would have too many variables. I think theres a way to solve for

*l*in terms of theta or theta in terms of

*l*but I'm not sure how to do it can anyone point me in the right direction.