Optimization problem involving an area and perimeter

Click For Summary

Homework Help Overview

The problem involves optimizing the dimensions of a rectangular pasture to minimize fencing while maintaining a specific area, as presented in a calculus textbook. The context is rooted in calculus, specifically dealing with optimization problems related to area and perimeter.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the setup of the problem, including the equations for perimeter and area. There is an exploration of differentiation to find extrema and a focus on potential algebraic simplifications. Questions arise regarding the correctness of the original poster's approach and the possibility of simplification leading to the book's answers.

Discussion Status

The discussion is ongoing, with participants providing insights and suggestions for simplification. There is no explicit consensus on the correctness of the original approach, but some guidance on algebraic manipulation has been offered.

Contextual Notes

Participants note a potential issue with the setup or simplification of the equations, and there is an acknowledgment of the original poster's uncertainty regarding algebraic skills. The problem is framed within the constraints of a homework assignment, which may limit the information available for discussion.

duncan idaho
Messages
2
Reaction score
0
My friend and I have come across this problem in Apostol's Calculus Vol. 1, ed.2 (exercises 4.21 if anyone is looking). We are studying calculus independently and have become stumped by this one.

Homework Statement



The problem as written in Apostol:
"A farmer wishes to enclose a rectangular pasture of area A adjacent to a long stone wall. What dimensions require the least amount of fencing?"

Homework Equations


From the problem setup, we have deduced two elementary equations:

P = 2x + y
A = xy

where P is the perimeter (or length of fence, minus the stone wall part) and A is area (a constant).

The Attempt at a Solution



There are two equations here and two variables. That seemed like a good thing. We found y = A/x and then substituted into the perimeter equation: P(x) = 2x + A/x.

In order to optimize, we differentiated P(x):

P`(x) = 2 - (A/x^2)

Then set the equation to 0 find the extrema and to solve for the variable x.

0 = 2 - (A/x^2)

2 = A/(x^2)

x^2 = A/2

x = (A/2)^1/2

And then substituted x into the area equation to find y:

y((A/2)^1/2) = A

y = (A/(A/2)^1/2))

According to the answer key this is wrong and we've been unable to find our error. It seems like something in the setup is wrong but we've reached a block. Does anyone have any insight into this?

Thank you in advance!
 
Physics news on Phys.org
Welcome to PF!

Hm, everything looks okay as far as I can tell. Did you try simplifying your answer? I wonder if the book isn't just listing this simplified form since
<br /> \frac{A}{\sqrt{\frac{A}{2}}}<br />
can be simplified.
 
I should have given the answer the book presented. Here it is:

x = ½√(2A)
y = √(2A)

I don't see how the solutions we got could be simplified into the solutions the book gives, however playing algebraically with roots is not my strongest skill. If this is just an algebraic situation I apologize in advance, but if anyone has some insight into this it is appreciated; I just want to make sure that our approach is sound.
 
Try using some of the properties listed at http://en.wikipedia.org/wiki/Square_root#Properties to help simplify your answer. That should help you get the answer listed in the book. And in general, can you simplify
<br /> \frac{a}{\frac{b}{c}} \; ?<br />
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
5
Views
2K
Replies
4
Views
3K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K