Optimizing Pulley Sizes for Speed Matching

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To match the speed of a tractor's pulley operating at 1100 RPM with a second machine requiring 650 RPM, the diameter of the second machine's pulley must be calculated. Using the formula for pulley ratios, the relationship between the RPMs and diameters can be established. The equation derived is 650 RPM = 1100 RPM * (10 inches / x), leading to the conclusion that the second pulley should have a diameter of approximately 16.923 inches. This ensures that the slower rotation of the second machine is achieved with a larger pulley size. The calculations confirm that a larger diameter pulley results in a slower RPM, aligning with the operational needs.
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Homework Statement


A tractor has a belt pulley diameter of 10 inch operating at 1100 revolutions per minute. The pulley is connected by a belt to another machine that needs to operate at 650 rpm. What size should the pulley be on the second machine?


Homework Equations


2Pi*r



The Attempt at a Solution


I don't really know where to start. I know that a wheels circumference is 2Pi*r
The first wheel is 10 inches so
2*Pi*5 inches = 1100rpm
if the second wheel has to operate at 650
can I get it by 650/2pi=103 inches?
 
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Set up a simple ratio.

\frac {1100} {10} = \frac {650} x
 
thank you
 
I'm still a bit unclear. Sorry.
If I set up a ratio
1100/10=650/x
I get an answer of 5.9
I need the second wheel to rotate slower but if it is smaller won't it spin faster?
 
I tried this again.
This seems to work.

driven pulley rpm= drive pulley rpm * drive pulley diameter/driven pulley diameter

650rpm=1100rpm*10inch/x
650x=11000
x=16.923 inch diameter for the pulley
 
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