Orbital Radius and Period: Doubling the Orbit

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SUMMARY

The discussion focuses on calculating the factor by which the orbital radius must be changed to double the orbital period of a satellite orbiting Earth. Using the formula T1/T2 = (r1/r2)^(3/2), the user derived that r1/r2 = (T1/T2)^(2/3), resulting in a value of approximately 1.59. This indicates that the orbital radius must be increased by a factor of 1.59 to achieve a doubled orbital period. The calculations align with established physics principles regarding orbital mechanics.

PREREQUISITES
  • Understanding of Kepler's laws of planetary motion
  • Familiarity with the formula for orbital period (T = 2π√(r^3/GM))
  • Basic algebra skills for manipulating equations
  • Knowledge of gravitational constants and mass of Earth (Mearth = 5.98 x 10^24 kg)
NEXT STEPS
  • Study the derivation of Kepler's Third Law of Planetary Motion
  • Learn about the implications of changing orbital radius on satellite dynamics
  • Explore gravitational effects on orbital mechanics using simulation tools
  • Investigate real-world applications of orbital period calculations in satellite deployment
USEFUL FOR

Students studying physics, aerospace engineers, and anyone interested in satellite dynamics and orbital mechanics.

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Homework Statement


A satellite is orbiting above the earth. By what factor must the orbital radius be changed in order to double the period of the orbit? (Mearth = 5.98 x 1024kg, Rearth = 6.36x106m)

The Attempt at a Solution


i got 1.59 by T1/T2=(r1/r2)^3/2 so r1/r2=(T1/T2) ^2/3 so 2^2/3 =1.59 but i have no clue if i did that right
 
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Looks okay to me. :approve:
 

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