Order of magnitude of the magnetic force

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SUMMARY

The discussion focuses on calculating the order of magnitude of the magnetic force required to maintain the circular motion of a proton with a mass of 1.7 x 10^-27 kg and a speed of 3 x 10^7 meters per second, moving in a circle of radius 200 meters. The relevant formula is derived from the Lorentz force equation, F=q(E+v x B), and the centripetal force equation, which states that the magnetic force (Lorentz force) must equal the centripetal force required for circular motion. The specific relationship established is qvB = (mv^2)/r.

PREREQUISITES
  • Understanding of Lorentz force and its components
  • Knowledge of centripetal force and its formula
  • Familiarity with basic physics concepts such as mass, velocity, and radius
  • Ability to manipulate scientific notation for calculations
NEXT STEPS
  • Calculate the magnetic field strength (B) using the derived formula
  • Explore the implications of varying the radius on the magnetic force
  • Investigate the effects of changing the speed of the proton on the required magnetic force
  • Learn about applications of the Lorentz force in particle accelerators
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Physics students, educators, and professionals in fields related to electromagnetism and particle physics will benefit from this discussion.

Nimmy
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A proton of mass 1.7 x 10^-27 kg and spped 3 x 10^7 meters per second is moving in a circle of a radius of 200 meters.

What formula do I need to use to find out the best estimate of the order of magnitude of the magnetic force needed to maintain this motion?
 
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The lorentz force.

F=q(E+v x B)
 
Any time something is traveling in a circle, it must be because of a centripedal force. In this case, the centripedal force is the lorentz force:

qvB = (mv^2)/r
 

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