The problem involves determining the frequency of a guitar string when its tension and length are altered. The original poster provides specific values for tension and length, along with a frequency for the initial conditions, and seeks clarification on the order of operations in their calculations.
The discussion is ongoing, with participants exploring the original poster's approach and questioning the assumptions made. Some guidance has been offered regarding the need for additional details and equations, but no consensus or resolution has been reached.
There is a mention of the original poster's background and their return to education, which may influence their understanding of the problem. Additionally, the need for clarification on the topic under which the problem is being addressed is noted.
A guitar string of length 60.0 cm under 81.0 N of tension produces a note of frequency 330.0 Hz. What frequency will the same string produce when under 100.0 N of tension and shortened to 25.0 cm?
Here is the question
[tex]f_{f}[/tex] = 330 Hz * [tex]\sqrt{ \frac{100.0 N}{81.0 N}}[/tex] * [tex]\frac{30.0 cm}{25.0 cm}[/tex]
Can you explain where I'm going wrong in my order of operations.When I try it I take 100.0 N and divide by 81.0 N where I get 1.234567901 and then I push the square root key on my calculator which gives me 1.111111111
I then take 330 * by 1.111111111 * 1.2
Which gives me 440 Hz.