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Order of the symmetry group of Feynman Diagrams

  1. Nov 3, 2014 #1
    Hello,

    I am learning Feynman diagrams and I still do not understad quite well the symmetry factor idea. The equation is:

    $$ \frac{1}{O(G)} = \frac{M}{n!(4!)^n} $$

    I was trying the next example:

    cIR6Sil.jpg

    If I am not wrong it is O(G) = 10 taking care of the asymmetry of each pair of internal lines connecting vertices.
     
  2. jcsd
  3. Nov 3, 2014 #2
    Now, I count S = O(G) = 12.
     
  4. Nov 22, 2014 #3
    Can anyone at least explain "for dummies" how to count the order of symmetry?
     
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