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Orientation on Calculus Work Problem. Hooke's Law.
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[QUOTE="Dan350, post: 4464523, member: 478791"] [b] A force of 16,000lb compresses a string from its natural length of 13 inch to 8 inch. Find the work done to compress it to the first inch[/b] [b] W=$$\int F dx$$[/b] [b] F=kx 16000=K(5) 3200=KW=$$\int F dx$$ W=$$\int_1^{13}\!\ 3200xdx$$ [1600x^2] from 1 to 13 w= 268800ftlb Am I right? I think the trick here is the limits. If they would be from 0 to 1,, aint that to little work? I mean, as you compress down, it's harder to do it. The work has to increase as you reach 0 inch Am I right? If not, please explain Or is it from 12 to 13? how I viewed is that they want to know the work as you compress it to the first inch.. in this case 1 I need a little orientation | 16000Lb | /----*------------------------*----------------------/ 0inch 1inch 8inch 13inc Thanks! [/b] [/QUOTE]
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Orientation on Calculus Work Problem. Hooke's Law.
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