Origin of the neutron diffusion angle formula

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Nafis Fuad
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I found this formula when I was studying neutron diffusion equation in Weston M. Stacey's book
Thanks in advance

cosβ=cosθx cosθ+sinθx sinθ cos(ψy−ψ)

Edited by moderator for clarity:
##\cos(\beta) = \cos(\theta_x)\cos(\theta) + \sin(\theta_x)\sin(\theta)\cos(\psi y - \psi)##
 
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How is the second line related to the first one?
Where do these variables come from and how are they related? The equation is not true in general.
 
Textbook figure 3.1 showing a coordinate system: a vertical z axis with angles theta, beta and psi, a differential area dA and a direction vector dr with position r(r, theta, psi).

Here it is
 
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  • Textbook figure 3.1 showing a coordinate system: a vertical z axis with angles theta, beta and psi, a differential area dA and a direction vector dr with position r(r, theta, psi).
    g3YfPZS.png
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##\psi - \psi_y## is the angle between the two planes of (one vector and x) and (the other vector and x).

We can imagine ##\beta##, ##\theta## and ##\theta_r## (as drawn) to form a triangle on a sphere with radius 1, with ##\psi - \psi_y## as angle between the last two. The problem is then standard geometry on a sphere, see e.g. Wikipedia.