Orthogonality of Matsubara Plane Waves

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SUMMARY

The discussion centers on the orthogonality relations of Matsubara frequencies in thermal field theory, specifically for bosons and fermions. For bosons, the orthogonality relation is expressed as \(\beta\delta_{n,-m}\), while for fermions, it is \(\beta\delta_{n,-(m+1)}\). The difference arises from the formulation of the exponential terms, leading to distinct conditions for orthogonality. The conversation clarifies that the Kronecker delta for fermions is not unusual but stems from the choice of frequency representation.

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  • Understanding of thermal field theory concepts
  • Familiarity with Matsubara frequencies for bosons and fermions
  • Knowledge of Kronecker delta notation
  • Basic proficiency in complex exponential functions
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Hi there!

In thermal field theory, the Matsubara frequencies are defined by [itex]\nu_n = \frac{2n\pi}{\beta}[/itex] for bosons and [itex]\omega_n = \frac{(2n+1)\pi}{\beta}[/itex] for fermions. Assuming discrete imaginary time with time indices [itex]k=0,\hdots,N[/itex], it is easy to obtain the following orthogonality relation for bosons, just by using the standard formula for the geometric series ([itex]\beta[/itex] is the inverse temperature),

[tex]\frac{\beta}{N} \sum_{k=0}^{N-1} \mathrm{e}^{\mathrm{i} \frac{\beta}{N} (\nu_n+\nu_m)k} = \begin{cases} \frac{\beta}{N} \sum_{k=0}^{N-1} 1 = \beta & \mathrm{for}\ n=-m \\ \frac{1-\mathrm{e}^{\mathrm{i} \beta (\nu_n+\nu_m)}}{1-\mathrm{e}^{\mathrm{i} \frac{\beta}{N} (\nu_n+\nu_m)}} = 0 & \mathrm{for}\ n\neq -m \end{cases} = \beta\delta_{n,-m}[/tex]

The second line holds because [itex]\beta (\nu_n+\nu_m)[/itex] is an integer multiple of [itex]2\pi[/itex] and thus the numerator vanishes. But in the case of fermions, I obtain

[tex]\frac{\beta}{N} \sum_{k=0}^{N-1} \mathrm{e}^{\mathrm{i} \frac{\beta}{N} (\omega_n+\omega_m)k} = \begin{cases} \frac{\beta}{N} \sum_{k=0}^{N-1} 1 = \beta & \mathrm{for}\ n=-(m+1) \\ \frac{1-\mathrm{e}^{\mathrm{i} \beta (\omega_n+\omega_m)}}{1-\mathrm{e}^{\mathrm{i}\frac{\beta}{N} (\omega_n+\omega_m)}} = 0 & \mathrm{for}\ n \neq -(m+1)} \end{cases} = \beta\delta_{n,-(m+1)}[/tex]

Is this true? The Kronecker delta with [itex]n,-(m+1)[/itex] looks rather strange!

Thanks for your help!
 
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It's not that strange, but it's a consequence of writing your exponential with a sum of frequencies instead of a difference. Consider the values around n = 0, [tex]\omega_{-1} = -T\pi[/tex], [tex]\omega_0 = T\pi[/tex], so for your orthogonality to hold, you need n = 0, m = -1, or n = -1, m = 0. If you choose to write the orthogonality with a difference, you should get n = m in both cases.
 
Thanks very much! I ask because I've encountered a sum of the above type (with a plus sign) while computing a two-point Green's function and I was wondering if the energy/frequency was conserved...
 

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