Oscillation of a Charged Particle

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SUMMARY

The discussion focuses on calculating the oscillation time of a charged particle placed on a thin torus with specific parameters: mass of 0.0001 kg, charge of -10^-5 C, inner radius of 0.05 m, outer radius of 0.1 m, and surface charge density of 10^-5 C. The participants explore the electric field generated by the torus using the equation for a charged ring and integration of infinitesimal rings. The conversation reveals confusion regarding the geometry of the torus and the correct approach to derive the oscillation time, emphasizing the need for clarity in definitions and mathematical expressions.

PREREQUISITES
  • Understanding of electric fields, specifically for charged rings and tori.
  • Proficiency in calculus, particularly integration techniques.
  • Familiarity with the concepts of oscillation and restoring forces in physics.
  • Knowledge of the properties of charged particles and their interactions with electric fields.
NEXT STEPS
  • Review the derivation of electric fields for charged rings and tori, focusing on integration methods.
  • Study the principles of oscillation in charged systems, particularly the relationship between force and displacement.
  • Learn about the potential energy of charged particles in electric fields to simplify calculations.
  • Examine the differences between thin and thick toroidal shapes in electrostatics.
USEFUL FOR

Students and researchers in physics, particularly those studying electromagnetism and oscillatory motion, will benefit from this discussion. It is also relevant for educators seeking to clarify concepts related to charged particles and their behavior in electric fields.

peroAlex
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Homework Statement


At our university we were given this problem: charged ball with mass of ##m = 0.0001 kg## and charge ##Q = -10^{-5} C## is placed on geometric axis of thin torus with inner radius of ##r_{inner} = 0.05 m##, outer radius of ##r_{outer} = 0.1 m## and surface charge density ##\sigma = 10^{-5} C##. Compute oscillation time for small deviation, this is when we only slightly flick the ball from stable state.

Homework Equations


First, I took a look at this article and a PDF presentation.

The Attempt at a Solution


Using the equation for electric field of a charged ring $$ E_z = \frac{Qz}{4 \pi \varepsilon_0 (r^2 + z^2)^{\frac{3}{2}}} $$ I tried obtaining formula for electric field of torus (wider ring) by integration infinitesimal rings from inner to outer radius. Using Symbolab I managed to obtain following equation $$ E_{torus} = \frac{Qz}{4 \pi \varepsilon_0} (\frac{r}{z^3 \sqrt{\frac{r^2}{z^2}+1}})_{r_{inner}} ^ {r_{outer}} $$.

From here on, I'm lost. Can somebody please help me or at least give me some guidance?
 
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Hi
peroAlex said:
Compute oscillation time for small deviation
means you are looking for something like the ##k## in ##\vec F = -k\vec x##. So if ##|\vec F|## is a more complicated function like what you have found it here, you simply want the linear development around the equilibrium position.
 
On 2nd reading I wonder if you are already aware of what I posted and are stuck in working out the electric field expression ?
peroAlex said:
I tried obtaining formula for electric field of torus (wider ring) by integration infinitesimal rings from inner to outer radius. Using Symbolab I managed to obtain following equation
Not clear what you are doing there. The exercise geves that the charge is at the surface and unfiormly distributed. Looks like the pdf assumes a thin torus (yours is fat).
 
I believe we're on the wrong footing here.

My task considers thin torus. Due to the fact that such configuration is composed of filamentary thin rings, I tried integration individual contributions (rings) from inner to outer radius.
 
Guy here (page 23) calls ##a/\rho = 5## fat. With ##a/\rho = 3##, yours is 67% fatter !
Surface charge on the inside is twice as close to the axis as surface charge on the outside !

Or do I have the wrong idea of inner (## r_{\rm inner} = 0.05## m) and outer (## r_{\rm outer} = 0.10## m) radius ?
 
Is the shape really a torus (donut-shaped)? If it is, the dimensions given seem to contradict the description that it's thin. Or is it supposed to be a flat ring of charge with the given inner and outer radii?
 
A washout ?!?

This is a torus
upload_2017-2-9_18-20-28.png


very clear what is meant with a torus in math and physics.

This is a washer (not a very scientific name, but clear enough)
upload_2017-2-9_18-24-3.png
 

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BvU said:
A washout ?!?

This is a torus
View attachment 112812

very clear what is meant with a torus in math and physics.

This is a washer (not a very scientific name, but clear enough)
View attachment 112814
This is the exact shape I was trying to describe. I'm so sorry for ambiguity in definition, English is not m native tongue.
 
Good; makes life easier. Thin disk with a hole in the center it is. I should have been more suspicious when you mentioned a 'wider ring' and called it a torus.
First expression in post #1 (field of charged ring) looks exactly as the one here , but with ##\ Q\ ## instead of ##\ 2\pi\sigma R' dR' , \ \ ## and -- apart from that -- seems OK to me. This you now want to integrate from ##r_{\rm min}## to ##r_{\rm max}## (instead of from ##0## to ##r_{\rm max}## like here) and there you lose me :

peroAlex said:
Using Symbolab I managed to obtain following equation
Using my common sense I got something else. Pretty unpleasant, but the first derivative at ##z=0## is what we are after and that should be fairly decent. (In fact, working out the potential instead of the E-field would have been more economical -- hindsight...)

One reason I don't trust your result is that it diverges for ##z=0## which should not happen. Could you check ?
 

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