Oscillation with Green's Function

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SUMMARY

The discussion focuses on solving an oscillator problem using Green's Function in the context of a force Fext(t) = F0[1−e(−αt)] acting on a mass-spring-damper system. The parameters are defined as b = m q and k = 4 m q², where q is a constant with units of inverse time. The solution derived involves a complex expression for x(t) using the Green's Function, but participants express difficulty in determining the final position without a specified final time. A suggestion is made to approach the problem using a simpler differential equation if Green's Function proves too challenging.

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Menteith
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Homework Statement


A force Fext(t) = F0[ 1−e(−αt) ] acts, for time t > 0, on an oscillator which is at rest at x=0 at time 0.
The mass is m; the spring constant is k; and the damping force is −b x′. The parameters satisfy these relations:
b = m q , k = 4 m q2 where q is a constant with units of inverse time.
Find the motion. Determine x(t); and hand in a qualitatively correct graph of x(t).
(B) Determine the final position.

Homework Equations


Green's Function:
x(t) = ∫-∞tF(t')G(t,t')dt'
where:
G(t,t') = (1/(m*ω1))*e-β(t-t')*sinω1(t-t') for t≥t'
= 0 for t<t'

The Attempt at a Solution


I have solved using green's function to obtain this mess:
(F0/m)*(e-βt/(β212))*((β/ω1)*sinω1t - cosω1t) - (F0/m)/((α-β)212)*[e-αt-e-βt*(cosω1t-((α-β)/ω1)sinω1t)]

From here, however, I am unsure of how to find the final position without the final time.
 
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The final position can be found by balancing the limiting force with Hook's law.
 
I would suggest you work the problem with a simple differential equation. The Green function approach for this one is rather difficult. If your instructor specified he requires a Green's function type solution, then it is the route you need to go, but for this one, the Green's function looks like a difficult approach. editing... I'm looking at the date on the OP. This one appears to be a couple of years old.
 

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