Oscillations and mechanical energy

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SUMMARY

The discussion centers on calculating the mechanical energy of a mass-spring system with an amplitude of 3.30 cm, a spring constant of 231 N/m, and a mass of 537 g. The mechanical energy is determined using the formula for potential energy in a spring, given by 1/2*k*delta x squared, where delta x is the amplitude. At maximum amplitude, the velocity is zero, thus the total mechanical energy is solely potential energy. The solution confirms that the amplitude serves as delta x in this context.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Familiarity with the concepts of potential and kinetic energy
  • Knowledge of basic mechanics and oscillatory motion
  • Ability to manipulate equations involving mass, spring constant, and amplitude
NEXT STEPS
  • Study the derivation of the potential energy formula for springs
  • Learn about the conservation of mechanical energy in oscillatory systems
  • Explore the relationship between amplitude and energy in harmonic motion
  • Investigate the effects of mass and spring constant on oscillation frequency
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory systems, as well as educators seeking to explain the principles of energy conservation in mass-spring systems.

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Homework Statement



A mass-spring system oscillates with an amplitude of 3.30 cm. If the spring constant is 231 N/m and the mass is 537 g, determine the mechanical energy of the system.


Homework Equations



Mechanical energy is potential energy plus kinetic energy

The Attempt at a Solution



How do I go about starting this problem?
 
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Are you familiar with the equation for the energy stored in a compressed (or extended) spring, in terms of k and delta-x?
 
1/2*k*delta x but I'm not given delta x am I? or is the amplitude delta x? and if it is then what do I use for velocity in the 1/2 mv^2 ?
 
it's 1/2*k*delta x squared. The max amplitude is your delta x, and since you're considering the situation at max amplitude, the velocity is zero, and so you have just potential energy.

Good luck!
Arjun
 
Thank you
 

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