Oscillations in an electric field

Click For Summary
SUMMARY

The discussion focuses on calculating the frequency of oscillation for a positive point charge q placed between two fixed positive point charges Q on the x-axis. The force exerted on charge q is derived from Coulomb's law, resulting in the equation F=Q*q/4∏ε0*-4ax/(a²-x²)². To find the frequency of oscillation, the force must be expressed in the form of Hooke's law, F=-kx, allowing the use of the formula f=1/(2∏)*√(k/m). The approximation |x| << a simplifies the analysis, enabling further calculations.

PREREQUISITES
  • Understanding of Coulomb's law and electric forces
  • Familiarity with Hooke's law and simple harmonic motion
  • Basic knowledge of calculus for approximating functions
  • Concept of oscillatory motion in physics
NEXT STEPS
  • Study the derivation of Hooke's law in the context of electric forces
  • Explore the concept of small-angle approximations in oscillatory motion
  • Learn about the principles of simple harmonic motion and its equations
  • Investigate the effects of varying charge configurations on oscillation frequency
USEFUL FOR

Physics students, educators, and anyone interested in understanding electric forces and oscillatory motion in charged systems.

evangoor
Messages
4
Reaction score
0

Homework Statement


Two positive point charges Q are held fixed on the x-axis at x=a and x=-a. A third positive point charge q, with mass m is them placed on the the x-axis away from the origin at a coordinate x such that lxl<<a. The charge q, which is free to move along the x-axis, is then released. Find the frequency of oscillation of the charge q.


Homework Equations


So I started with the force equation for charges where FE=1/(4∏ε0)*qqq2/r2
I figured I need to get it into a form of Hooke's law where F=-kx. So I could then use the equation f=1/(2∏)*[itex]\sqrt{k/m}[/itex]

The Attempt at a Solution


So I wrote the force equations which each of the fixed charges would exert on the point charge and added them together resulting in F=Q*q/4∏ε0*-4ax/(a2-x2)2. From here I did not see how I could get it into a form of Hooke's law. At this point I am at a loss of what path to take. Help would be greatly appreciated.
 
Last edited:
Physics news on Phys.org
Since |x| << a, approximate the denominator.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 19 ·
Replies
19
Views
2K
Replies
3
Views
1K
Replies
5
Views
1K
Replies
9
Views
2K
Replies
23
Views
5K