Oscillations in an LC circuit (Question from Irodov)

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SUMMARY

The discussion focuses on oscillations in an LC circuit, specifically analyzing the relationship between frequency (ω), capacitance (C), and energy conservation. A key equation presented is ω = 1/√(LC), which indicates that increasing ω by a factor of n results in a change of distance (d) to n²d. The participant, after initial confusion regarding energy conservation, concludes that the total energy of LC oscillations is not constant and derives a relationship for maximum charge (Qmax) as a function of distance. The final assertion is that work done in the circuit is zero under the assumption of no current change.

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Anubhav
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Homework Statement
1. The problem statement, all variables and given/known data
In an oscillating circuit consisting of of a parallel-plate capacitor and an inductance coil with negligible active resistance the oscillations with energy are sustained. The capacitor plates were slowly drawn apart to increase the scillation frequency -fold. What work was done in the process?
Relevant Equations
Variables have meaning as usual
€=permitivity of vaccum
Energy in LC oscillations =W
Energy of charged capacitor=(Q^2)/2C
Force between plates of parallel plate capacitor=(Q^2)/2€A
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16195584671893895411783627819363.jpg
 
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For those who want to read it without breaking their neck ...

I can also decipher another relevant equation (## \ \omega = \displaystyle {1\over\sqrt{LC}}\ ##)
So inceasing ##\omega## n times means changing ##\ d \rightarrow n^2d\ ##.
Unclear to me what is conserved -- is ##\ q\ ## the same as ##\ Q_{\text{max}}\ ## ? and is that invariant ?
Then where does the mechanical work energy go ?

##\ ##
 
I'm sorry for inconvenience ..I shall delete this thread and reframe the entire Q properly again
 
Pinging @DaveE

Congratulations with the badge ! I'm sure there is no broom, and I'm certain they don't have cookies either (my clumsy way to distinguish you from @davenn)​
@Anubhav shouldn't apologize too much. Plenty effort demonstrated. I'm just filing away at his (her?) assumptions to test them. Can you handle this one in a more didactically responsible way :smile: ?

I ask myself: Would there be much difference between this case of changing ##d## and the DC case ?

##\ ##
 
BvU said:
Pinging @DaveE

Congratulations with the badge ! I'm sure there is no broom, and I'm certain they don't have cookies either (my clumsy way to distinguish you from @davenn)​
@Anubhav shouldn't apologize too much. Plenty effort demonstrated. I'm just filing away at his (her?) assumptions to test them. Can you handle this one in a more didactically responsible way :smile: ?

I ask myself: Would there be much difference between this case of changing ##d## and the DC case ?

##\ ##
Hello sir..Thanks for your I read your reply and gave it a thought again...
Also I have posted a typed image of Question as certain elements were missing in Q which I wrote
I am happy to inform you that after discussion with my friends I was able to solve it and got the right answer.
Actually I had assumed the Total energy of LC oscillations to be constant. Obviously that was wrong.
In my another attempt I wrote Change in energy of LC oscillations [i.e change in Qmax^2/(2C)] as function of integration of F(x).dx (where x is distance between plates)
Differentiation of this leads to a differential equation solving which gives Qmax as function of x..
Then change in energy of LC oscillations gives Total work done.
Ans comes out to be W(n-1)
Screenshot_20210428-183828~2.png
 
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Assumption: current does not change. (No dissipation, is like amperian currents in a permanent magnet).
So:
## V_C \rightarrow nV_C ##
## V^2_C \rightarrow n^2V^2_C ##
## C \rightarrow C/n^2 ##
So ## 1/2 ~CV_C^2 ## is unchanged; inductance energy is unchanged; circuit energy is unchanged; work = 0.

Probably wrong somewhere.Probably assumption of no current change.
 
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