Oscillations with fluid and pendulum

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SUMMARY

The discussion focuses on the dynamics of oscillations involving a hollow sphere and fluid mechanics, specifically how water influences motion without exerting torque about its center. The inertia moment for the hollow sphere is defined as 2mr²/3 + ml², leading to the equation (2mr²/3 + ml²)θ'' = -mglθ. The conversation also highlights the importance of the parallel axis theorem in calculating the moment of inertia (MoI) about the point of suspension, indicating that while water does not contribute to the inertia moment, it can exert torque at the suspension point.

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Homework Statement
A pendulum is constructed as a light thin-walled sphere of
radius R filled up with water and suspended at the point 0 from a
light rigid rod (Fig. 4.1.1). The distance between the point 0 and the
centre of the sphere is equal to 1. How many times will the small
oscillations of such a pendulum change after the water freezes? The
viscosity of water and the change of its volume on freezing are to
be neglected
Relevant Equations
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That's a good question, i am not sure how the water in liquid state will influence in the motion, but i imagine that can not exert any torque, i would say in the first case:

Hollow sphere inertia moment: 2mr²/3 + ml²
(2mr²/3 + ml²)θ'' = -mglθ (1)

In the second case, otherwise, we will have
2(m+m')r²/5 + (m+m')l² = -(m+m')glθ

Anyway, i am certain that have some error in (1), something say to me that the water can indeed exert a torque although it doesn't contribute to inertia moment, but, as i don't know the mechanics of a fluid, i am not sure.
 
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LCSphysicist said:
Hollow sphere inertia
The shell is light and can be ignored.
The water does not exert a torque about its centre, but it still exerts a torque about the point of suspension. What does the parallel axis theorem give for its MoI about that point?
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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