Otto cycle combustion heat question

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SUMMARY

The discussion centers on calculating the temperature during the combustion stage of an ideal Otto cycle, specifically addressing the miscalculation that resulted in an unrealistic temperature of 51,161 Kelvin. The user utilized the heat of combustion of gasoline (42,500 kJ), a specific heat of air (0.834 kJ/kg·K), and an initial temperature of 662.385 Kelvin. Key insights reveal that the enthalpy of formation for both fuel and products must be considered, and the correct air-fuel ratio of 14.7 is crucial for accurate calculations.

PREREQUISITES
  • Understanding of the Otto cycle and its thermodynamic principles
  • Familiarity with heat of combustion values for gasoline
  • Knowledge of specific heat capacity, particularly for air
  • Basic concepts of enthalpy and energy balance in combustion reactions
NEXT STEPS
  • Research the impact of air-fuel ratios on combustion efficiency
  • Learn about the enthalpy of formation for various fuels and combustion products
  • Explore advanced thermodynamic calculations in the context of the Otto cycle
  • Investigate the effects of varying specific heat capacities on combustion temperature predictions
USEFUL FOR

Engineers, automotive technicians, and students studying thermodynamics or internal combustion engines will benefit from this discussion, particularly those focused on optimizing engine performance and efficiency.

Saharka
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I have been trying to determine the efficiency of an ideal Otto cycle based on the compression ratio of my car and the heat of combustion of gasoline and I think I'm not entierly wrong but there is something quite off. When trying to calculate the temperature of the combustion stage my result gives me the amazingly high temperature of 51,621kelvin which is obviously silly.
Here is the data I used:

I used the heat of combustion of gasoline, in this case 42,500 Kj as Qin.
662.385kelvin as the temperature of the previous stage of the cycle.
0.834 Kj/KgK as the sepecific heat of air.

So according to me the temperature should be given by the following equation:

Qin=CvΔT

So I need one of the temperatures so it becomes:

T3=(Qin/Cv)+T2

Which translates to:

T3=(42,500/0.834)+662.385

And finally:

T3= 51,161kelvin

I suspect that I'm using the wrong number for the specific heat of air but I'm not entierly sure, any ideas?
 
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You have ok numbers for air. The problem is that you only took into account part of the energy balance. You need to consider the enthalpy of formation for fuel and products, not just the fuel. Remember, you don't get those product bonds without an energy exchange.
 
Thanks for the reply, but I'm still confused, I thought the heat of combustion already considered the enthalpy of formation of the products or am I missing the point?
 
Saharka said:
Thanks for the reply, but I'm still confused, I thought the heat of combustion already considered the enthalpy of formation of the products or am I missing the point?
Right.
But you are using 1 kg of gasoline, by combustion, to raise the temperature of 1 kg of air.
Would that be correct?
https://en.wikipedia.org/wiki/Air–fuel_ratio
 
Ohhh right, should have been a duh, thanks.

So no I think the air fuel ratio is 14.7 I'll adjust for this thanks again.
 

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