MHB Oxidation Numbers: Fe203+3CO to 2Fe+3CO2

  • Thread starter Thread starter markosheehan
  • Start date Start date
  • Tags Tags
    Numbers Oxidation
Click For Summary
In the reaction Fe2O3 + 3CO → 2Fe + 3CO2, iron (Fe) is reduced as it gains electrons, while carbon (C) is oxidized as it loses electrons. The oxidation states are clarified by expressing the ions: Fe3+ and O2- for iron oxide, and C2+ and O2- for carbon monoxide. It is noted that while valency can guide the determination of oxidation numbers, it is not always accurate, as seen with carbon's valency of 4 compared to its oxidation state of +2 in this reaction. Oxygen consistently has an oxidation state of -2 in compounds, and the oxidation number of a compound must equal zero. Understanding these principles is essential for accurately identifying oxidation and reduction in chemical reactions.
markosheehan
Messages
133
Reaction score
0
By using oxidation numbers can someone show me what is oxidised and reduced

Fe203+3co->2Fe+3co2
 
Mathematics news on Phys.org
markosheehan said:
By using oxidation numbers can someone show me what is oxidised and reduced

Fe203+3co->2Fe+3co2

Hi Marko,

Making the ion forms explicit, we have:
$$
{Fe^{3+}}_2{0^{2-}}_3+3C^{2+}O^{2-}\to 2Fe+3C^{4+}{O^{2-}}_2
$$
So $Fe$ gains electrons and as such it is reduced.
And $C$ loses electrons, meaning it is oxidized.
 
I like Serena said:
Hi Marko,

Making the ion forms explicit, we have:
$$
{Fe^{3+}}_2{0^{2-}}_3+3C^{2+}O^{2-}\to 2Fe+3C^{4+}{O^{2-}}_2
$$
So $Fe$ gains electrons and as such it is reduced.
And $C$ loses electrons, meaning it is oxidized.

thanks
I usually go to the periodic table and look at the elements valency and then i take this as the oxidation number. this is not always correct though?
for example carbon has a valency of 4 but in the above equation it is 2+.
so you go off the ones you know like oxygen is always -2 and the oxidation number of a compound must always equal zero.
 
markosheehan said:
thanks
I usually go to the periodic table and look at the elements valency and then i take this as the oxidation number. this is not always correct though?
for example carbon has a valency of 4 but in the above equation it is 2+.
so you go off the ones you know like oxygen is always -2 and the oxidation number of a compound must always equal zero.

Yes, in compounds oxygen is always -2.
The metals (that are oxidized) usually have more than one oxidation number, and the valency doesn't even have to be one of them (copper for example).
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K