A photon of energy E strikes an electron at rest and undergoes pair production, producing a positron and an electron:
photon + (e-) = (e+) + (e-) + (e-)
The two electrons and the positron move off with identical momenta in the direction of the initial photon. Find the kinetic energy of the three final particles and find the energy E of the photon.
2.[tex]E_0=mc^2[/tex]*rest energy of photon = 0.
The Attempt at a Solution
The initial momentum of the photon is mc, and this gives an initial kinetic energy of 2mc2. This is equal to the final kinetic energy, and since each particle has the same momentum then the kinetic energy of each is 2mc2/3.
My problem comes with finding the energy of the photon. The book gives an answer of 4mc2, and I'm not sure how to get that. Any help is appreciated.