1. The problem statement, all variables and given/known data Two parallel plates, each having area A = 3118cm2 are connected to the terminals of a battery of voltage Vb = 6 V as shown. The plates are separated by a distance d = 0.35cm. You may assume (contrary to the drawing) that the separation between the plates is small compared to a linear dimension of the plate. A dielectric having dielectric constant κ = 2.6 is now inserted in between the plates of the capacitor as shown. The dielectric has area A = 3118 cm2 and thickness equal to half of the separation (= 0.175 cm) . What is the charge on the top plate of this capacitor? 2. Relevant equations C=Q/V C(new) = KC(old) 3. The attempt at a solution I really have no idea. I tried dividing the new capacitance by (because the dielectric is d/2 long) and calculating Q from that, but that didn't work.