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kjlchem
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Homework Statement
Two parallel plates, each having area A = 3118cm2 are connected to the terminals of a battery of voltage Vb = 6 V as shown. The plates are separated by a distance d = 0.35cm. You may assume (contrary to the drawing) that the separation between the plates is small compared to a linear dimension of the plate.
A dielectric having dielectric constant κ = 2.6 is now inserted in between the plates of the capacitor as shown. The dielectric has area A = 3118 cm2 and thickness equal to half of the separation (= 0.175 cm) . What is the charge on the top plate of this capacitor?
Homework Equations
C=Q/V
C(new) = KC(old)
The Attempt at a Solution
I really have no idea.
I tried dividing the new capacitance by (because the dielectric is d/2 long) and calculating Q from that, but that didn't work.