Parallel and perpendicular part of a vector

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The discussion revolves around resolving a force vector into components parallel and perpendicular to specified lines, AB and BC. The participant is struggling with their calculations and questions whether their setup and methodology are correct, specifically regarding the use of cosine and sine functions for parallel and perpendicular components. There is a suggestion to verify the accuracy of the initial diagram, as discrepancies between the diagram and expected answers are noted. Despite attempts to adjust calculations based on feedback, the participant remains uncertain about the correctness of their approach. The conversation highlights the importance of accurate diagram representation and understanding vector resolution methods.
cytochrome
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Homework Statement


Resolve the force F into

a) a part perpendicular to AB and

b) a part parallel to BC


Homework Equations


a dot b = ab*cos(θ)


The Attempt at a Solution


I attached my attempt in the .pdf file. For some reason it is wrong. I don't understand how my reasoning is incorrect.

The orange square in the picture is a supposed to be a wooden box in the problem, so that detail is not important to the problem.
 

Attachments

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First, you might want to check the angle given by arctan (3/5).
 
SteamKing said:
First, you might want to check the angle given by arctan (3/5).

Thanks for pointing that out, but the answer still comes out to be wrong even if I change that. Am I setting up the problem wrong?

Do you do F*cos(θ) to find a parallel component of F and F*sin(θ) to find a perpendicular part of F in general?
 
cytochrome said:
Thanks for pointing that out, but the answer still comes out to be wrong even if I change that. Am I setting up the problem wrong?
Are you sure that your initial diagram is correct? The given answers do not seem to match the diagram.

Do you do F*cos(θ) to find a parallel component of F and F*sin(θ) to find a perpendicular part of F in general?
Yes.
 
Doc Al said:
Are you sure that your initial diagram is correct? The given answers do not seem to match the diagram.


Yes.

Yes my diagram is correct. It's possible the solutions could be wrong, it's out of an old book... Anyways, I was wondering if my methodology was correct.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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