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Introductory Physics Homework Help
Calculating Electron Speed Between Parallel Charged Plates
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[QUOTE="Clara Chung, post: 5513575, member: 550045"] [h2]Homework Statement [/h2] An electron is emitted by an electron gun which is midway between two parallel charged plates which are 20 cm apart. The electrical field strength between the plates is20 N C^-1. The electron is attracted towards the positive plate and strikes the plate as shown. If the electron is emitted at a speed of 3 x 10^6 ms^-1, find the speed of the electron just before striking the positive plate. photo(not necessary) : [URL]http://s613.photobucket.com/user/Yan_Wa_Chung/media/03_zpskzvvveir.png.html[/URL][h2]Homework Equations[/h2] v^2 = 2as(not sure) , e=1.60 x 10^(-19) C , mass of electron = 9.11 x 10^(-31) kg [h2]The Attempt at a Solution[/h2] Why is the answer 8.9 x 10^6 ms-1? I got a value about 3x10^6 because the width of the plates is small and it can't gain much vertical speed. vertical acceleration = 20 x 1.60 x 10^(-19) / 9.11 x 10^(-31) = 3.51 x 10^(12) m s^-2 by v^2 = 2as v^2 = 2 (3.51 x 10^(12)) (10/100) = 7.02 x 10^(11) speed = [[7.02 x 10^(11)] + (3x 10^6)^2] 1/2 =3.11 x 10^6 ms-1 or by energy conservation, (3x10^6)^2/2 + 20 x 1.60 x 10^(-19) / 9.11 x 10^(-31) (work done) = speed^2/2 speed=3.11 x 10^6 ms-1 what's wrong with my calculation? [/QUOTE]
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Calculating Electron Speed Between Parallel Charged Plates
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