(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Hi everyone, I'm new here at posting but have found this forum very useful in the past. I have hit a snag with a capacitor problem... any thoughts?

Assume you have a parallel plate capacitor separated by one cm of air and one cm of a dielectric with a dielectric constant of six. What fraction of the voltage between the two plates is across the air? Look up the breakdown strength of air and calculate the voltage when the air will begin to discharge.

ε = 6

ε^{0}= 1.0059

d = 1 cm

Breakdown strength of air is 3MV/m

2. Relevant equations

V= I X

X = 1/jωC = d/(j ε ε^{0}A)

V= I d / j ω A Ɛ Ɛ_0

3. The attempt at a solution

I started trying to add the capacitances of the two dielectics together in series, however, can I assume that the capacitance will divide according to their dielectric constants?

That is the voltage gradient will be 6 times stronger over the air compared to the dielectric?

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# Homework Help: Parallel Plate Capacitor Conundrum

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