Undergrad Parallel vector, I need a bit of explanation

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To determine vector u such that uc + d is parallel to i + 3j, it is essential to understand the relationship between the components of parallel vectors. Specifically, vectors ai + bj and ci + dj are parallel if the ratio b/a equals d/c. In this case, for the vector to align with i + 3j, the condition b = 3a must hold, which explains the multiplication of the 3 with i. The concept of parallelism indicates that the direction of the vectors must be the same, reinforcing the need for consistent ratios in their components. This clarification helped the original poster grasp the solution better, leading to the conclusion that the thread is resolved.
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TL;DR
If we are making the vector parallel to i+3j, why do we multiply 3 with the i of the resultant vector ?
Given that c = 3i + 4j and d = i - 2j, find u if uc + d is parallel to i + 3j,

this is the question

in the solution,
it says that we have to multiply the 3 with the i

i do know that this is the ”method“ to do this question but I’d like a bit of explanatio.
I don’t understand why the 3 is multiplied with the i when in the question it says 3j.

thank you for your time.
 

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Hint:
What is the vector ## \mu c + d## in terms of i and j? What does it mean for one vector to be parallel to another?

-Dan
 
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The answer the OP, vectors ai + bj and ci + dj will be parallel if b/a = d/c. So vector ai + bj will be parallel to i + 3j if b = 3a. This is where the factor 3 comes from.
 
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topsquark said:
Hint:
What is the vector ## \mu c + d## in terms of i and j? What does it mean for one vector to be parallel to another?

-Dan
If one vector is parallel that means the direction is the same. In terms of i and j the parallel vectors are always some multiple of the direction
 
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DrClaude said:
The answer the OP, vectors ai + bj and ci + dj will be parallel if b/a = d/c. So vector ai + bj will be parallel to i + 3j if b = 3a. This is where the factor 3 comes from.
This speaks to me a lot. If something is parallel, the ratio of x to y lengths should be the same. Thank you very much. It makes so much more sense now.
I’ll propos this thread solved. Thank you all.
i love the way that you teach stuff
 
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