Finding unknown given vector a,b and parallel

  • Thread starter Thread starter xplosiv3s
  • Start date Start date
  • Tags Tags
    Parallel Vector
Click For Summary

Homework Help Overview

The problem involves determining the scalar μ such that the vector expression μc + d is parallel to the vector i + 3j, where c and d are given vectors.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conditions for vector parallelism and the implications of multiplying components. There is confusion regarding the correct approach to equate the components of the vectors involved.

Discussion Status

Some participants have provided insights into the nature of parallel vectors and questioned the original poster's method of equating components. There is an ongoing exploration of the reasoning behind the multiplication of components and the implications of vector relationships.

Contextual Notes

Participants express uncertainty about the steps taken in the solution process and the assumptions made regarding vector equality and parallelism.

xplosiv3s
Messages
13
Reaction score
0

Homework Statement



Given that c= 3i + 4j and d= i - 2j

find μ when μc + d is parallel to i +3j



Homework Equations





The Attempt at a Solution



3iμ + 4jμ + i + j

i( 3μ + 1) + (4μ -2) j

since it is parallel to i + 3j therefore 3μ+1=3(4μ-2)

giving μ = 7/9

However μ = -1


Additional information:
Apparently (see bold) I am supposed to multiply the LHS by 3 instead of the RHS but by equating I and J vectors and looking at the parallel line it would seem logical to do it the way I have (or am I being retarded?). I can accept that I have the multiply LHS instead of RHS but I don't understand why!
 
Physics news on Phys.org
xplosiv3s said:

Homework Statement



Given that c= 3i + 4j and d= i - 2j

find μ when μc + d is parallel to i +3j



Homework Equations





The Attempt at a Solution



3iμ + 4jμ + i + j

i( 3μ + 1) + (4μ -2) j

since it is parallel to i + 3j therefore 3μ+1=3(4μ-2)
Not necessarily. Vectors can be parallel without being equal. Two vectors are parallel if either of them is some nonzero scalar multiple of the other.
xplosiv3s said:
giving μ = 7/9

However μ = -1


Additional information:
Apparently (see bold) I am supposed to multiply the LHS by 3 instead of the RHS but by equating I and J vectors and looking at the parallel line it would seem logical to do it the way I have (or am I being retarded?). I can accept that I have the multiply LHS instead of RHS but I don't understand why!
 
Mark44 said:
nonzero scalar multiple of the other.

So i multiply the other side by 3 because it has to be that? ^
 
xplosiv3s said:
So i multiply the other side by 3 because it has to be that? ^

If a vector is parallel to i+3j, then 3 times the i component is equal to the j component. Since 3*1=3. So 3*(3μ+1)=(4μ-2). I'm not sure why you are doing it the other way around.
 
Dick said:
If a vector is parallel to i+3j, then 3 times the i component is equal to the j component. Since 3*1=3. So 3*(3μ+1)=(4μ-2). I'm not sure why you are doing it the other way around.

Ok thanks! That kinda makes sense!

actually nvm >.>
 
I can understand why everyone hates vectors
 
xplosiv3s said:
I can understand why everyone hates vectors
Vectors are marvelous !
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
3K
Replies
18
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K