Parallel vs anti parallel electron spin

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SUMMARY

The discussion centers on the spin configurations of a hydrogen atom's electron and proton, specifically addressing whether parallel or anti-parallel spins are energetically favorable. The consensus is that anti-parallel spins represent the lower energy configuration due to the attraction between opposite magnetic poles, which can be understood through quantum mechanics rather than classical magnetic dipole theory. The Heitler-London model and hyperfine interactions are also relevant concepts in this context, particularly in relation to spectral line splitting.

PREREQUISITES
  • Quantum mechanics fundamentals
  • Understanding of magnetic dipole interactions
  • Familiarity with the Heitler-London model
  • Knowledge of hyperfine interactions in atomic physics
NEXT STEPS
  • Research the Heitler-London model in detail
  • Study hyperfine interactions and their implications in atomic physics
  • Learn about the energy of magnetic dipoles in a magnetic field
  • Explore the concept of spectral line splitting in quantum mechanics
USEFUL FOR

Students and educators in physics, particularly those focusing on quantum mechanics, atomic structure, and magnetic interactions, will benefit from this discussion.

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Homework Statement


a hydrogen atom with its electron in the ground state 1s orbital can have proton and electron spins that are either parallel or anti parallel. which is the lower configuration and why? treat the electron as orbiting the proton in a plane perpendicular to the spin of the proton.


Homework Equations


the Heitler London model may have something to do with it but I am not sure.
i also know that the splitting of spectral lines is due to the property of spin


The Attempt at a Solution



im pretty sure the answer is anti parallel but i have no idea why. this was assigned for a general physics class which i think is crazy since we never even talked about anything like this. Please Help or steer me in the right direction or something. thanks
 
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I suggest you look up the hyperfine interaction. Hydrogen is a famous case leading to the 21 cm hydrogen line used in radio astronomy.
 
Without calculations, I would answer based on opposite poles of magnets attracting. For a bit more detail, use the energy of a magnetic dipole in a B field.
 
Cruikshank said:
Without calculations, I would answer based on opposite poles of magnets attracting. For a bit more detail, use the energy of a magnetic dipole in a B field.

The classical solution of magnetic field and dipoles is incorrect in this case. It turns out you have to use quantum mechanics to get the right solution for this problem.
 

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