- #1

Calcgeek123

- 20

- 0

## Homework Statement

Find the equation of the tangent line to f(t)=<cot(t),csc(t)> at the point (1/sq.rt of 3, 2/sq.rt of 3)

## Homework Equations

n/a

## The Attempt at a Solution

I started by finding the slope, y'/x', so I got csc(t)cot(t)/csc^2(t). I then used the equation of a line, y=mx+b. Doesn't a tangent line have the opposite slope? So I think i'd plug in 2/sq.rt of 3 for y, csc^2(t)/csc(t)cot(t) for the slope, 1/sq.rt of 3 for x, and then solve for b. Do I need to plug in my x and y points though into the slope? Then that gets tough because I don't know what csc^2(1/sq. rt of 3) is. Any suggestions?