Parametric equation for a cycloid

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The discussion focuses on the challenges of reversing the parametric equations of a cycloid, specifically the equations x = R(θ - sin(θ)) and y = R(1 - cos(θ)). Users express difficulty in isolating θ in terms of x and y, noting that the non-parametric equation x = ±cos⁻¹((R - y)/R) ± √(2Ry - y²) complicates the process. The consensus is that there is no straightforward analytical solution due to the transcendental nature of the equations, and numerical methods are recommended for finding solutions. The potential application of the Lambert W function is also mentioned as a possible avenue for exploration.

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Hi, I am having trouble reversing the formula x=R(\theta - \sin(\theta)) to get \theta in terms of x. Am I missing something obvious or is it just impossible?

To put it into context this is part of the parametric equation for a cycloid. The other part of the parametric equation is y = R (1- \cos(\theta)). Setting R to 1 (the radius of the rolling wheel) does not seem to help. The non parametric equation for the cycloid is \pm \cos^{-1}((R-y)/R) \pm \sqrt{2 R y -y^2}. I would also like to reverse this full equation to get y in terms of x but I am having trouble with that too. The reason I am trying to reverse the equations is that I am trying to get the intersection of two loci (the cycloid locus and the perimeter of a ellipse).

Any help appreciated. Thanks :)
 
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In general, there is no "formula" for solving an equation in which the unknown number occurs both inside a transcendental function (such as cosine) and outside it. typically, the best that can be done is a numerical solution.

I ahve no idea what you mean by "The non parametric equation for the cycloid is \pm \cos^{-1}((R-y)/R) \pm \sqrt{2 R y -y^2}" because that is not an equation. Did you leave something out?
 
HallsofIvy said:
In general, there is no "formula" for solving an equation in which the unknown number occurs both inside a transcendental function (such as cosine) and outside it. typically, the best that can be done is a numerical solution.

I ahve no idea what you mean by "The non parametric equation for the cycloid is \pm \cos^{-1}((R-y)/R) \pm \sqrt{2 R y -y^2}" because that is not an equation. Did you leave something out?

Yes I did! That should read "The non parametric equation for the cycloid is x = \pm \cos^{-1}((R-y)/R) \pm \sqrt{2 R y -y^2}" which is obtained by substituting \pm \cos^{-1}((R-y)/R) for \theta in x=R(\theta - \sin(\theta)).


It seems ridiculous that there is no easy solution to the question "If the point on the perimeter of a wheel has advanced linearly by x then what angle has the wheel rotated through?"
 
Last edited:
Can the Lambert W function help here?
 

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