Why Must ##\mu_1, \mu_2## = ##\mu_1^*, \mu_2^*##? Parametric Resonance

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The discussion centers on the necessity for the parameters ##\mu_1, \mu_2## to equal ##\mu_1^*, \mu_2^*## in the context of parametric resonance. It is established that if ##\mu_1\mu_2 = \mu_1^*\mu_2^* = 1## and ##\mu_1 + \mu_2 = \mu_1^* + \mu_2^*##, then the equality holds. The participants explore the implications of complex conjugates and provide a mathematical breakdown using the variables u1 and u2, represented as complex numbers. The discussion emphasizes the importance of these relationships in proving the equality of the parameters.

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Why ##\mu_1, \mu_2## must be the same as ##\mu_1^*, \mu_2^*## ?

What I thought is : If ##\mu_1\mu_2 = \mu_1^*\mu_2^*## and ##\mu_1+\mu_2 = \mu_1^*+\mu_2^*##, then ##\mu_1, \mu_2## are the same as ##\mu_1^*, \mu_2^*##

It can be shown by taking the complex conjugate of (27.5) that $$\mu_1\mu_2 = \mu_1^*\mu_2^*=1$$
Now it is to be proven that ##\mu_1+\mu_2 = \mu_1^*+\mu_2^*##.
Any help would be appreciated.
 
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If u1 = (a + bi) and u2 = (c + di), then you can write (a + bi)(c + di) = 1. Expanding it, you get:

ac + adi + bci – bd = 1. Rearrange as (ac – bd) + i(ad + bc) = 1. So (ac – bd) = 1, and (ad + bc) = 0. You may be able to get a starting point from that. If possible, I will try to come back and revisit this.
 
scottdave said:
If u1 = (a + bi) and u2 = (c + di), then you can write (a + bi)(c + di) = 1. Expanding it, you get:

ac + adi + bci – bd = 1. Rearrange as (ac – bd) + i(ad + bc) = 1. So (ac – bd) = 1, and (ad + bc) = 0. You may be able to get a starting point from that. If possible, I will try to come back and revisit this.
Thanks for your help. But still could not get it.
 

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