Parametric to Cartesian Conversion: Troubleshooting and Identifying Mistakes

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SUMMARY

The discussion focuses on converting the parametric equations x(t) = (1-t^2)/(1+t^2) and y(t) = 2t/(1+t^2) into Cartesian form. The user attempted to substitute t = tan u, leading to incorrect transformations of the equations. The mistake identified involves the misapplication of trigonometric identities, specifically the incorrect use of the identity for y(t), which should be y(t) = 2tan(u)/(1 + tan^2(u)). Correcting this identity is crucial for achieving the accurate Cartesian representation.

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I have the parametric function x(t) = (1-t^2)/(1+t^2), y(t) = 2t/(1+t^2) and need to eliminate the parameter and find a Cartesian equation.

I've tried to substitute t = tan u, then x(t) = cos(2u) and y(t) = tan(2u). From that I get y = sin(2x)/x. However, when I entered the original parametric function into a grapher, I get an entirely different graph. Where did I go wrong?
 
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autre said:
I've tried to substitute t = tan u, then x(t) = cos(2u) and y(t) = tan(2u).

I'm not getting that for the y(t) equation. I think it's because you got your identity confused.
[tex]\frac{2\tan u}{1 - \tan^2 u} = \tan 2u[/tex]
(minus in the denominator)

But here we have:
[tex]y(t) = \frac{2\tan u}{1 + \tan^2 u} = \frac{2\tan u}{\sec^2 u} = ...[/tex]
 

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