Parity and total angular momentum

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SUMMARY

The discussion focuses on calculating parity and total angular momentum for even-even nuclei, specifically those with magic numbers such as oxygen-16 (8O8) and calcium-40 (20Ca20). It is established that for even/even nuclei, all pairs of nucleons cancel each other, resulting in a ground state of 0+. The participant expresses confusion regarding the orbital angular momentum being zero despite the presence of nucleons in the p-shell, indicating a need for further clarification on this topic.

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  • Understanding of nuclear physics concepts, specifically parity and angular momentum.
  • Familiarity with magic numbers in nuclear structure.
  • Knowledge of nucleon configurations in shells, particularly the p-shell.
  • Basic grasp of quantum mechanics principles related to angular momentum.
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gdonoso94
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Hi,

I'd like to know how to calculate parity and total angular momentum of nuclei which have even Z and even N and also Z and N are magic numbers, such as 8O8 or 20Ca20 (the number before the element is Z and the after one is N).

I don't know how to insert LaTeX formulas.

Thank you in andvance
 
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For even/even nuclei, all pairs cancel each other, so you always have 0+ in the ground state.
 
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Likes   Reactions: gdonoso94
Thanks for your reply. I knew that, but I don't understand why orbital angular momentum is 0, because you have nucleons, for example in p-shell... I don't know if I have explained me...
 

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