- #1
shinobi20
- 267
- 19
Homework Statement
Given n=(x + iy)/2½L and n*=(x - iy)/2½L
Show that ∂/∂n = L(∂/∂x - i ∂/∂y)/2½ and ∂/∂n = L(∂/∂x + i ∂/∂y)/2½
Homework Equations
∂n Ξ ∂/∂n, ∂x Ξ ∂/∂x, as well as y.
The Attempt at a Solution
∂n=(∂x + i ∂y)/2½L
Apply complex conjugate on right side, ∂n=[(∂x + i ∂y)/2½L] * [(∂x - i ∂y)/(∂x - i ∂y)].
∂n=( (∂x)2 + (∂y)2) / 2½ L (∂x - i ∂y)
I'm stuck, I think if (∂x)2 + (∂y)2=1 I can think of a way. But ugh... Any suggestions?