1. The problem statement, all variables and given/known data Given n=(x + iy)/2½L and n*=(x - iy)/2½L Show that ∂/∂n = L(∂/∂x - i ∂/∂y)/2½ and ∂/∂n = L(∂/∂x + i ∂/∂y)/2½ 2. Relevant equations ∂n Ξ ∂/∂n, ∂x Ξ ∂/∂x, as well as y. 3. The attempt at a solution ∂n=(∂x + i ∂y)/2½L Apply complex conjugate on right side, ∂n=[(∂x + i ∂y)/2½L] * [(∂x - i ∂y)/(∂x - i ∂y)]. ∂n=( (∂x)2 + (∂y)2) / 2½ L (∂x - i ∂y) I'm stuck, I think if (∂x)2 + (∂y)2=1 I can think of a way. But ugh... Any suggestions?