Partial derivative second order

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SUMMARY

The discussion focuses on calculating the second-order partial derivative of a function using the quotient rule and chain rule. The user initially struggles with the approach but successfully derives the expression for the second derivative, resulting in \(\frac{-r^2 + 3x^2}{r^5}\). Participants confirm the correctness of the solution and emphasize that both the quotient rule and chain rule yield the same result, highlighting a matter of personal preference in method selection.

PREREQUISITES
  • Understanding of partial derivatives
  • Familiarity with the quotient rule in calculus
  • Knowledge of the chain rule in calculus
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus
  • Explore advanced topics in partial derivatives, such as mixed partial derivatives
  • Learn about the implications of the second-order partial derivatives in optimization problems
  • Review examples of using the quotient rule with different types of functions
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Students learning multivariable calculus, educators teaching calculus concepts, and anyone seeking to deepen their understanding of partial derivatives and their applications.

Taylor_1989
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Homework Statement


Hi guys, I am have a problem with the question displayed below:

upload_2017-2-15_23-33-6.png
[/B]

Its 6.1 ii) I am really not sure how I am suppose to approach this. I am new to partials, so any advice would be great.

Homework Equations

The Attempt at a Solution


So far I have:
$$\frac{\partial ^2 f}{\partial x^2}=\frac{\partial}{\partial x}\frac{\partial f}{\partial x}=\frac{\partial}{\partial x}\frac{-x}{r^3} $$

using quotient rule:

$$=[\frac{\partial}{\partial x}(-x)(r^3)-(-x)(\frac{\partial}{\partial x}r^3)]/r^6$$

$$\frac{\partial}{\partial x}r^3=3r^2\frac{\partial r}{\partial x}=3r^2*(x/r)=3rx$$

subbing the above into the quotient and simplifying
I get
$$\frac{-r^2+3x^2}{r^5}$$

[/B]
 
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Taylor_1989 said:
using quotient rule:
might not be the best thing to do. How did you find ##\partial f\over\partial x## ?
And: was 6 i) all right and clear ? How come 6 ii) is then problematic ?

[edit] Stupid me o:) . Your working is completely correct. Well done...
'Quotient rule' confused me, but it works just fine. My approach would be to use the chain rule -- with, of course, the same result. Matter of preference, not matter of 'best thing to do'.
 
Last edited:
Taylor_1989 said:

Homework Statement


Hi guys, I am have a problem with the question displayed below:

View attachment 113277[/B]

Its 6.1 ii) I am really not sure how I am suppose to approach this. I am new to partials, so any advice would be great.

Homework Equations

The Attempt at a Solution


So far I have:
$$\frac{\partial ^2 f}{\partial x^2}=\frac{\partial}{\partial x}\frac{\partial f}{\partial x}=\frac{\partial}{\partial x}\frac{-x}{r^3} $$

using quotient rule:

$$=[\frac{\partial}{\partial x}(-x)(r^3)-(-x)(\frac{\partial}{\partial x}r^3)]/r^6$$

$$\frac{\partial}{\partial x}r^3=3r^2\frac{\partial r}{\partial x}=3r^2*(x/r)=3rx$$

subbing the above into the quotient and simplifying
I get
$$\frac{-r^2+3x^2}{r^5}$$
[/B]

Your answer is correct. It is a matter of taste whether you leave your final numerator as ##3x^2-r^2##, or re-write it as ##2x^2-y^2-z^2##.

BTW: Remove all those offensive bold fonts: it looks like you are yelling at us.
 
thank for the responses. I will remove bold next, i did not even notice it was bold.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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