Partial Derivatives: Calculating fₓ and fᵧ (3,1)

Click For Summary

Homework Help Overview

The discussion revolves around calculating the partial derivatives of a function defined as f(x,y) = g(x-2y), where g is a function of a single variable. The specific point of interest is the evaluation of the partial derivatives at the point (3,1).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the chain rule in the context of partial derivatives. There is an emphasis on understanding the meaning of partial derivatives and the importance of keeping other variables constant during differentiation.

Discussion Status

The conversation includes various attempts to clarify the approach to finding the partial derivatives. Some participants suggest showing working steps to aid understanding, while others highlight the need to apply the chain rule correctly.

Contextual Notes

There is a mention of the derivative of g at a specific point, which may be relevant to the calculations, but the exact relationship to the partial derivatives is not fully explored in the discussion.

Jessica21
Messages
5
Reaction score
0
Hi everyone!

I was wondering if someone could help me with the following question with partial derivatives.

A function f: R^2 -> R is defined by f(x,y) = g(x-2y), where g: R-> R.
If g'(1)= 3, calculate f subscript x (3,1) and f subscript y of (3,1).

thanks!
 
Physics news on Phys.org
You can use the little X2 icon to type fx and fy.

Do you know the chain rule for this setup:

g is a function of u and u is a function of x and y, then

gx = ? and gy = ?

That's what you need.
 
hi jessica21, welcome to pf ;) usually it helps if you show some working...

i would start by trying to find the partial derviatives of f & thinking about what a partial derviative means

[tex]f_x = \frac{\partial f}{\partial x} = \frac{\partial }{\partial x} g(x-2y)[/tex]
 
also remember a partial derivative means the other variables are kept constant in the differentiation
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
26
Views
4K