Partial Fraction Decomposition for (s^2+1)^2 - Homework Help

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Homework Help Overview

The discussion revolves around the partial fraction decomposition of the expression \(\frac{1}{(s^{2}+1)^{2}}\). Participants are exploring methods to break down this expression for the purpose of performing an inverse Laplace transform.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts various forms of partial fraction decomposition, including expressions involving complex numbers and polynomial terms. Some participants question the necessity of breaking down the expression further and suggest alternative approaches.

Discussion Status

Participants are actively engaging with the problem, offering hints and questioning the assumptions about the coefficients in the decomposition. There is a mix of interpretations regarding how to combine terms and what forms are valid for the decomposition.

Contextual Notes

Some participants note that the original expression is not suitable for their current resources, as it does not appear in their Laplace transform tables. There are discussions about the nature of the coefficients being real or complex, which may affect the decomposition process.

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Homework Statement


How to break down:
[tex]\frac{1}{(s^{2}+1)^{2}}[/tex]
into partial fractions?


Homework Equations


-


The Attempt at a Solution


I have tried:
[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{1}{(1+i)^{2}\times(1-i)^{2}} = \frac{A}{(s+i)} + \frac{B}{(s+i)^{2}} + \frac{C}{(s-i)}} + \frac{D}{(s-i)^{2}}[/tex]

and

[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{As+B}{(s^{2}+1)^{2}} + \frac{Cs+D}{(s^{2}+1)}[/tex]

and

[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{As+B}{(s^{2}+1)} + \frac{Cs+D}{(s^{2}+1)}[/tex]

but none of them works..
Please help
 
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Hi v_bachtiar! :wink:

Why isn't 1/(s2 + 1)2) good enough as it is? :confused:

But if you do want to break it down further, your first try should have worked …

what did you get? :smile:
 
It is not good enough because I need to perform an inverse Laplace transform on the fraction.
And at my level, I only use tables and some basic theorems (convolution, shift in s etc.) and 1/(s2 + 1)2) is not on the table :(

I have attached my working using the first try..
 

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Hi v_bachtiar! :smile:

What makes you think A B C and D are real? :rolleyes:

Hint: to simplify it, what are 1/(s - i) ± 1/(s + i) and 1/(s - i)2 ± 1/(s + i)2 ? :wink:
 
They are 2s/(s2+1) or 0
and
(2s2-2)/(s2+1)2 or 4si/(s2+1)2

so..

(As-Ai+Cs+Ci) / (s2+1) + (B(s+i)2+D(s-i)2) / ((s2+1)2) = 1

and As-Ai+Cs+Ci = 2s , B(s+i)2+D(s-i)2 = 2s2-2

is this right?
 
oh, i mean:

(As-Ai+Cs+Ci) + (B(s+i)2+D(s-i)2) = 1
 
Hi v_bachtiar! :smile:

(just got up :zzz: …)
v_bachtiar said:
They are 2s/(s2+1) or 0
and …

No, 2s/(s2+1) or 2i/(s2+1) :redface:

ok, rewrite them as

(2s3+s)/(s2+1)2 or i(2s2+2)/(s2+1)2

Now can you see how to easily combine them with the others to get 1/(s2+1)2 ? :smile:
 
v_bachtiar said:

Homework Statement


How to break down:
[tex]\frac{1}{(s^{2}+1)^{2}}[/tex]
into partial fractions?


Homework Equations


-


The Attempt at a Solution


I have tried:
[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{1}{(1+i)^{2}\times(1-i)^{2}} = \frac{A}{(s+i)} + \frac{B}{(s+i)^{2}} + \frac{C}{(s-i)}} + \frac{D}{(s-i)^{2}}[/tex]

and

[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{As+B}{(s^{2}+1)^{2}} + \frac{Cs+D}{(s^{2}+1)}[/tex]

and

[tex]\frac{1}{(s^{2}+1)^{2}} = \frac{As+B}{(s^{2}+1)} + \frac{Cs+D}{(s^{2}+1)}[/tex]

but none of them works..
Please help
u can do as
A/s^2+1 + BX/(S^2+1)2
 
tiny-tim said:
Hi v_bachtiar! :smile:

(just got up :zzz: …)


No, 2s/(s2+1) or 2i/(s2+1) :redface:

ok, rewrite them as

(2s3+s)/(s2+1)2 or i(2s2+2)/(s2+1)2

Now can you see how to easily combine them with the others to get 1/(s2+1)2 ? :smile:


hi tiny-tim,

you mean combine (add) them with (2s2-2)/(s2+1)2?

so 1 = (2s3+s) + (2s2-2)

then, where do I imply the A, B, C, and D? :confused:

(thank you for your help so far) :smile:
 
  • #10
How about (2s2+2) and (2s2-2) ? :wink:
 

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