Partial Vs. Complete differentials when dealing with non-independent variables

Click For Summary

Discussion Overview

The discussion revolves around the differentiation of multi-variable functions under constraints, specifically focusing on the transition between complete and partial derivatives. Participants explore the implications of holding certain variables constant while differentiating, and the relevance of the terms involved in the differentiation process.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions why derivatives change from complete to partial when moving from the expression for differentials to the desired partial derivative, particularly in the context of a constraint.
  • Another participant provides an interpretation of the terms in the expression, explaining that the first term represents the usual partial derivative, while the second term accounts for the change in the function due to the dependency of variables.
  • A later reply suggests that the notation for differentials does not align with the regular and partial derivatives, raising questions about the behavior and definitions of differentials in this context.
  • One participant proposes a renaming strategy to clarify the relationship between the variables and the function, suggesting that solving for one variable as a function of others may simplify the differentiation process.
  • Geometric interpretations are also discussed, with one participant describing how constraining movement along a surface affects the relationship between the variables and the function value.

Areas of Agreement / Disagreement

Participants express varying interpretations of the transition from complete to partial derivatives and the implications of the terms involved. There is no consensus on a definitive explanation for the notation or the behavior of differentials, indicating ongoing debate and exploration of the topic.

Contextual Notes

Participants note the complexity of the notation and the potential for confusion regarding the definitions and behaviors of differentials versus derivatives. The discussion includes assumptions about variable independence and the implications of constraints that remain unresolved.

raxAdaam
Messages
32
Reaction score
0
I'm brushing up on differentiating multi-variable functions subject to a constraint and was curious about the notation. In particular, why the derivatives change from complete to partial derivates. I've illustrated the question with an example, below. My specific question w.r.t. the example is in bold.

For example, if [itex]w = w(x,y,z)[/itex] is subject to the constraint [itex]g(x,y,z) = c[/itex], where c is a constant. To find [itex]\left(\frac{\partial w}{\partial y}\right)_z[/itex] using differentials, we would first write:

[itex]dw = w_x dx + w_y dy + w_z dz[/itex]

Because we are interested in the case where [itex]z[/itex] is held constant [itex]dz = 0[/itex], which leaves us with:

  1. [itex]dw = w_x dx + w_y dy[/itex].

    Now, in order to find [itex]\left(\frac{\partial w}{\partial y}\right)_z[/itex], we use the constraint to find an expression for [itex]dx[/itex] in terms of [itex]dy[/itex], skipping the steps, this comes out to be:
  2. [itex]dx = -\frac{g_y}{g_x}dy[/itex],


    where [itex]g_{\alpha} = \frac{\partial g}{\partial \alpha}[/itex] is just convenient shorthand. Plugging this expression for [itex]dx[/itex] into #1, rearranging and factoring out the [itex]dy[/itex], we have:
  3. [itex]dw = \left[w_y-w_x\frac{g_y}{g_x}\right]dy[/itex]

My question arises here: as I understand, the differentials in #3 are "complete" (i.e. not partial); however, if we want to go from #3 to the desired expression, viz. [itex]\left(\frac{\partial w}{\partial y}\right)_z[/itex], they become partial differentials - why?

A related question that interests me is how one would interpret these two elements on the RHS of #3 - I understand where each comes from entirely, so I'm not looking for a literal translation from the math to English, I'm trying to understand the relevance of the terms. I see that [itex]w_y[/itex] is simply the partial derivative w.r.t. [itex]y[/itex] in the case that the variables were all independent, but how to understand the other term and why it has the form that it does?
 
Physics news on Phys.org
I managed to answer the second question (I think / I hope!) & thought I'd post it in case anyone was curious.

The first term [itex]w_y = \frac{\partial w}{\partial y}[/itex] is just the usual partial, as mentioned above.

Now the significance of the second term becomes clearer if one writes out the equivalent form of [itex]\frac{g_y}{g_x}[/itex], viz. because [itex]g(x,y,z) = 0[/itex] we have (holding [itex]z[/itex] constant: [itex]dg = 0 = g_x dx + g_y dy[/itex] which gives us [itex]\frac{g_y}{g_x} = -\left(\frac{\partial x}{\partial y}\right)_z[/itex] and the answer above becomes:

[itex]\left( \frac{\partial w}{\partial y} \right)_z = w_y + w_x\cdot \left(\frac{\partial x}{\partial y}\right)_z[/itex]

so in the second term we are adding the additional change in [itex]w[/itex] caused by [itex]x[/itex] varying in response to the change in [itex]y[/itex] (which is what we would expect, I realize now - but the negative sign was confusing).

If there is a more salient (or geometric) interpretation - I'd be very interested to hear!
 
Any thoughts or clarifications on this? Am very keen to understand what's happening here ...
 
raxAdaam said:
#3 [itex]dw = \left[w_y-w_x\frac{g_y}{g_x}\right]dy[/itex]

My question arises here: as I understand, the differentials in #3 are "complete" (i.e. not partial); however, if we want to go from #3 to the desired expression, viz. [itex]\left(\frac{\partial w}{\partial y}\right)_z[/itex], they become partial differentials - why?

A related question that interests me is how one would interpret these two elements on the RHS of #3 - I understand where each comes from entirely, so I'm not looking for a literal translation from the math to English, I'm trying to understand the relevance of the terms. I see that [itex]w_y[/itex] is simply the partial derivative w.r.t. [itex]y[/itex] in the case that the variables were all independent, but how to understand the other term and why it has the form that it does?


As far as the differentials not being partial, two things. First thing, we have the notation [itex]dx[/itex], [itex]\frac{\partial}{\partial x}[/itex], and [itex]\frac{d}{dx}[/itex]. No idea why derivatives have a regular and partial version, and differentials don't. That is an interesting question. Second thing is, that partial also has a z on it, which the differential doesn't have that either. I'm just going to make a wild guess and say that it has something to with theoretical mathematician's realizing that differentials are more well behaved, and don't require a lot of policing, but I'm not sure. I think you were observant to notice that, and it's good that you are seeing all the mechanisims that are going on. And the notation in math is not perfect, you are welcome to make your own system, maybe notes in the margins about what is being held fixed when.

But here's another way I might help, it may even help with the differentials. I like to be careful about naming things. For instance, from the constraint, we are to solve for x as a function y and z, so enforcing g=c implies we can find for x(y,z). So we have w(y,z)=w(x(y,z),y,z). The left side doesn't look right, so I like to rename it, v(y,z)=w(x(y,z),y,z). So we really want v_y. Which is w_x*x_y+w_y. So renaming things got me to where I want to go a little quicker.


raxAdaam said:
If there is a more salient (or geometric) interpretation - I'd be very interested to hear!

Umm, geometrically, you are constraining yourself to move along the g=c surface. Now you take a z-slice, and the intersection of the z-slice with the g=c surface is a curve. Now let y vary, and staying on that curve tells you how the other dependent variables change, which in turn detemrines how the f value changes.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 1 ·
Replies
1
Views
13K