I Particle on a cylinder with harmonic oscillator along z-axis

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The discussion focuses on the Hamiltonian of a spin-less particle confined to a cylinder with a harmonic potential along the z-axis, specifically examining the eigenvalues and eigenvectors. The proposed Hamiltonian is correctly separated into components for a particle on a ring and a harmonic oscillator, leading to eigenfunctions of the form |ψ⟩=|m⟩|n⟩. The calculated eigenvalues, E= (n²ħ²)/(2mR²) + ħω(n + 1/2), are confirmed to be correct. The impact of a perturbation like εcos(φ) is assessed, concluding that it has no effect at the fundamental level due to the absence of angular momentum. The discussion seeks validation on the correctness of the total Hamiltonian eigenvectors and the treatment of the perturbation.
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I need to know if I have solved the following problem well:

A spin-less particle of mass m is confined to move on the surface of a cylinder of infinite height with a harmonic potential on the z-axis and Hamiltonian ##H=\frac{p_z^2}{2m}+\frac{L_z^2}{2mR^2}+\frac{1}{2}m\omega^2z^2## and I need to calculate its eigenvalues and eigenvectors.
I thought of separating the Hamiltonian as it is written in the text, and find the Hamiltonian of a particle on a ring and a harmonic oscillator along the z-axis with eigenfunctions of the type ##|\psi\rangle=|m\rangle|n\rangle## where ##m## are the eigenvalues of ##L_z## equal to ##\frac{1}{\sqrt{2\pi}}e^{im\phi}## and ##n## are the eigenvalues of the harmonic oscillator. For the eigenvalues I had thought they were ##E=\frac{n^2\hbar^2}{2mR^2}+\hbar\omega(n+1/2)##. Is this right?
Also, if I had a perturbation like ##\epsilon cos(\phi)## to calculate on the fundamental level I could say by eye that its effect is zero since in the fundamental level there is no angular momentum?
 
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You have to write ##\mu## for the mass to distnguish if from the eigenvalue of ##\hat{L}_z##, ##m \hbar##. Then ##E_{mn}=m^2\hbar^2/(2\mu R^2)+\hbar \omega (n+1/2)##, where ##m \in \mathbb{Z}##, ##n \in \mathbb{N}_0##.
 
Thank you @vanhees71 for the answer, so the eigenvalues are correct, what about the total Hamiltonian eigenvectors? Are they correct? And the perturbation?
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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