Particle Position @t=0 to t=8 sec: I'm Wrong?

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SUMMARY

The discussion centers on calculating the displacement of a particle from its initial position at t=0 to t=8 seconds using a velocity graph. The initial assumption of 8 m/s as the displacement is incorrect; the correct approach involves interpreting the area under the velocity vs. time graph to determine displacement. Participants clarify that displacement is not the same as velocity and emphasize the importance of understanding the relationship between position change and the geometry of the graph.

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You are looking for a displacement, not a velocity, which is what you answer is.

You have a velocity graph and have to find a displacement from it?

What is the relationship between the change in an objects position, and the geometry of a velocity vs. time graph?
 

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