1. The problem statement, all variables and given/known data A particle moves along the x-axis so that at time t≥0 its position is given by: x(t)= t^3-2t^2-4t+6. For what value(s) of t where 0≤t≤4 is the particle's instantaneous velocity the same as its average velocity on [0,4]? 3. The attempt at a solution So I got the average velocity: v(4)-v(0)/ (4-0) = 22-6/(4-0) = 4 = avg velocity for v(t) So then would I solve the derivative of the position function to find what value of t in the derivative would make x'(t)= 4? Thanks in advance.