Particle through magnetic field

  • #1

Homework Statement


A particle enters perpendicular to a magnetic field with a speed of 100,000 m/s. The magnetic field has a strength (B) of 0.80 T. The particle starts doing a spinning motion with an 0.1m radius. The particle charge is +3e (three elementary charges). Calculate the mass of the particle.

Homework Equations


Since it does a spinning motion, we need the formula for centripetal motion. F=m(v^2/r). We also need a formula that gives us F based on B and Q (charge) and v (speed). For that we have F = QvB.

The Attempt at a Solution


We set them equal.

m(v^2/r)=QvB and we can take off one v.
m(v/r)=QB, we move the things around so we have m alone
m*v = rQB => m = rQB / v

We enter everything that is known and we get:

0.1 * (3*1.6*10^-19) * 0.80 split by 100,000.

Result: 3.84 × 10^-25 kg. Am I correct?
 

Answers and Replies

  • #2
20
0
Before we answer your question, do you think you are correct?
 
  • #3
Before we answer your question, do you think you are correct?
I do!
 
  • #4
20
0
Ok, actually whenever you believe you are correct, you should just be confident and not doubt yourself.
You are correct in this question!
 

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