• Support PF! Buy your school textbooks, materials and every day products Here!

Particle through magnetic field

  • #1

Homework Statement


A particle enters perpendicular to a magnetic field with a speed of 100,000 m/s. The magnetic field has a strength (B) of 0.80 T. The particle starts doing a spinning motion with an 0.1m radius. The particle charge is +3e (three elementary charges). Calculate the mass of the particle.

Homework Equations


Since it does a spinning motion, we need the formula for centripetal motion. F=m(v^2/r). We also need a formula that gives us F based on B and Q (charge) and v (speed). For that we have F = QvB.

The Attempt at a Solution


We set them equal.

m(v^2/r)=QvB and we can take off one v.
m(v/r)=QB, we move the things around so we have m alone
m*v = rQB => m = rQB / v

We enter everything that is known and we get:

0.1 * (3*1.6*10^-19) * 0.80 split by 100,000.

Result: 3.84 × 10^-25 kg. Am I correct?
 

Answers and Replies

  • #2
20
0
Before we answer your question, do you think you are correct?
 
  • #3
Before we answer your question, do you think you are correct?
I do!
 
  • #4
20
0
Ok, actually whenever you believe you are correct, you should just be confident and not doubt yourself.
You are correct in this question!
 

Related Threads on Particle through magnetic field

Replies
11
Views
615
Replies
4
Views
1K
Replies
7
Views
969
Replies
7
Views
571
Top